Question

String strPrimaryNav = "MEN";
String strSecondaryNav = "Shoes";
String strTertiaryNav = "Golf";

driver.findElement(By.linkText(strPrimaryNav)).click();

WebElement weSecNav = driver.findElement(By.className("secondaryButton").linkText(strSecondaryNav));

Mouse mouse = ((HasInputDevices) driver).getMouse();
mouse.mouseDown(((Locatable)weSecNav).getCoordinates());
//just trying with for loop as the tertiary popup disappears quickly and hence getting ElementNotVisible Exception
for (int i = 0 ; i< 2; i++){
    mouse.mouseDown(((Locatable)weSecNav).getCoordinates());
    //mouse.mouseMove(((Locatable)weSecNav).getCoordinates(), 0, 0 );
    //WebElement weTerNav = driver.findElement(By.className("tertiaryButton").linkText(strTertiaryNav));
    WebElement weTerNav = driver.findElement(By.linkText(strTertiaryNav));
    boolean isSecDisplayed = ((RenderedWebElement)weTerNav).isDisplayed();
    System.out.println("isDisplayed: " + isSecDisplayed);
    System.out.println(" " + ((RenderedWebElement)weSecNav).getAttribute("href"));
    System.out.println(" " + ((RenderedWebElement)weSecNav).getValueOfCssProperty("action"));
    weTerNav.click();
}

我使用selenium 2尝试下面的代码但是，第三个弹出窗口不会长时间点击它，因此在第三次点击时获得ElementNotVisible异常。

Answer 1

在发送点击之前，您至少可以检查元素是否可见：

Selenium s = new WebDriverBackedSelenium( driver, URL );
s.waitForCondition( "!( document.getElementById('.....') === null )", "20000" );
s.click( .... );

这可以避免异常。我不确定是否有办法让弹出窗口保持不变。

如何在Selenium 2 API中处理Mouseover

1 个答案: