Question

我正在尝试使用TypeORM中的自定义ManyToMany字段保存实体

主要实体

@Entity()
export class Routine extends BaseEntity {
  @PrimaryGeneratedColumn()
  id: number;

  @Column('varchar', { length: 50 })
  name: string;

  @Column('timestamptz')
  creationDate: Date;

  @Column('boolean')
  active: boolean;

  @ManyToOne(
    type => User,
    user => user.routines,
    { eager: false },
  )
  user: User;

  @Column()
  userId: number;

  @OneToMany(
    type => ExerciseToRoutine,
    exerciseToRoutine => exerciseToRoutine.routineId,
  )
  public exerciseToRoutine: ExerciseToRoutine[];
}

JoinTable

@Entity()
export class ExerciseToRoutine extends BaseEntity {
  @PrimaryColumn()
  exerciseId: number;

  @PrimaryColumn()
  routineId: number;

  @Column()
  day: number;

  @ManyToOne(
    type => Routine,
    routine => routine.exerciseToRoutine,
  )
  routine: Routine;

  @ManyToOne(
    type => Exercise,
    exercise => exercise.exerciseToRoutine,
  )
  exercise: Exercise;
}

试图保存实体的代码

const routine = new Routine(name, currentDate, user, exerciseToRoutine, false);
    await this.trySaveRoutine(routine);

问题在于，在自动生成常规ID之前，我需要将Routine实体及其executionToRoutine（JoinTable转换为Exercise Entity）保存起来，而属性ExerciseToRoutine需要该ID。那么我应该怎么做呢？谢谢

Answer 1

OneToMany的{{1}}字段exerciseToRoutine不会存储到Routine的任何外键，这将自行执行联接表。要保存新的ExerciseToRoutine实体，只需将Routine字段设置为空数组即可。然后使用新生成的exerciseToRoutine id创建一个ExerciseToRoutine。

如何保存自定义的ManyToMany表TypeORM

1 个答案: