我有以下模型:
class Administrator(models.Model):
// code
def __str__(self):
title = 'Administrator ' + str(self.pk)
return title
这将返回对象的标题,例如Administrator 1
,Administrator 2
等
如何为title
返回list_display
中的ModelAdmin
?:
class AdministratorAdmin(ModelAdmin):
model = Administrator
list_display = ('pk', 'id', 'title???')
答案 0 :(得分:1)
我认为应该是:
class AdministratorAdmin(ModelAdmin):
model = Administrator
list_display = ('pk', 'id', '__str__')