Question

行['conus_days']> 0或行['conus_days1']> 0：返回行['conus_days'] * 8 +行['conus_days1'] 12 elif（row ['Country'] =='Afghanistan'或row ['Country'] =='Iraq'或row ['Country'] =='Somalia'或row ['Country'] =='也门'）并且row ['oconus_days']> 0或row ['oconus_days1']> 0：返回行['oconus_days'] 12 +行['oconus_days1'] * 8 elif（row ['Country'] =='Afghanistan'或row ['Country'] =='Iraq'或row ['Country'] =='Somalia'或row ['Country'] =='也门'）：返回行['days_in_month'] * 12 elif（row ['Country'] =='Germany'）和row ['conus_days']> 0：返回row ['conus_days'] * 8 + row ['conus_days1'] 10 elif（row ['Country'] =='Germany'）：返回行['days_in_month'] 10 elif row ['Country'] =='Conus'：返回行['working_days'] * 8 其他：返回行['working_days'] * 8 预测['hours'] = Forecast.apply（lambda行：get_hours（row），axis = 1）打印（forecast.head（））

这将返回以下输出：

          Name      EID  Start Date   End Date      Country  year  Month  \
0        xx       123456 2019-08-01 2020-01-03  Afghanistan  2020      1   
1        XX      3456789 2019-09-22 2020-02-16        Conus  2020      1   
2        xx.      456789 2019-12-05 2020-03-12        Conus  2020      1   
3        DR.      789456 2019-09-11 2020-03-04         Iraq  2020      1   
4        JR.      985756 2020-01-03 2020-05-06      Germany  2020      1   

   days_in_month start_month  end_month  working_days  conus_mth  oconus_mth  \
0             31  2020-01-01 2020-01-31            21          8           1   
1             31  2020-01-01 2020-01-31            21          9           2   
2             31  2020-01-01 2020-01-31            21         12           3   
3             31  2020-01-01 2020-01-31            21          9           3   
4             31  2020-01-01 2020-01-31            21          1           5   

   conus_days  conus_days1  oconus_days  oconus_days1  hours  
0           0            0            2            25    224  
1           0            0            0             0    168  
2           0            0            0             0    168  
3           0            0            0             0    372  
4           1           28            0             0    344

-第4行的输出不正确，应返回288

Answer 1

通过用双括号关闭每个if语句，可以使每个if语句单独且准确地运行。

def get_hours（row）：如果（（row ['Country'] =='Afghanistan'或row ['Country'] =='Iraq'或row ['Country'] =='Somalia'或row ['Country'] =='也门）和（row ['conus_days']> 0或row ['conus_days1']> 0））：返回行['conus_days'] * 8 +行['conus_days1'] 12 如果（（row ['Country'] =='Afghanistan'或row ['Country'] =='Iraq'或row ['Country'] =='Somalia'或row ['Country'] =='也门）和row ['oconus_days']> 0或row ['oconus_days1']> 0）：返回行['oconus_days'] 12 +行['oconus_days1'] * 8 if（row ['Country'] =='Afghanistan'或row ['Country'] =='Iraq'或row ['Country'] =='Somalia'或row ['Country'] =='Yemen'）：返回行['days_in_month'] * 12 if（（row ['Country'] =='Germany'）and row ['conus_days']> 0）：返回row ['conus_days'] * 8 + row ['conus_days1'] * 10 if（（row ['Country'] =='Germany'）and row ['oconus_days']> 0）：返回row ['oconus_days'] * 10 + row ['oconus_days1'] 8 if（row ['Country'] =='Germany'）：返回行['days_in_month'] 10 如果（row ['Country'] =='Conus'）：返回行['working_days'] * 8 其他：返回行['working_days'] * 8 预测['hours'] = Forecast.apply（lambda行：get_hours（row），axis = 1）打印（forecast.head（））

       Name      EID  Start Date   End Date      Country  year  Month  \

0 XX。 123456 2019-08-01 2020-01-03阿富汗2020 1
1 xx 3456789 2019-09-22 2020-02-16 Conus 2020 1
2 Mh 456789 2019-12-05 2020-03-12 Conus 2020 1
3 DR 789456 2019-09-11 2020-03-04伊拉克2020 1
4 JR 985756 2020-01-03 2020-05-06德国2020年1

days_in_month start_month end_month Working_days conus_mth oconus_mth \ 0 31 2020-01-01 2020-01-31 21 8 1
1 31 2020-01-01 2020-01-31 21 9 2
2 31 2020-01-01 2020-01-31 21 12 3
3 31 2020-01-01 2020-01-31 21 9 3
4 31 2020-01-01 2020-01-31 21 1 5

conus_days conus_days1 oconus_days oconus_days1小时
0 0 0 2 25 224
1 0 0 0 0 168
2 0 0 0 0 168
3 0 0 0 0 372
4 1 28 0 0 288

熊猫函数问题-方程输出不正确

1 个答案: