遍历C中的Char数组元素

时间:2020-01-02 19:59:04

标签: c binary

该代码应采用用户的输入并将其转换为二进制。输入被分组为一个整数数组以存储字符代码和/或相邻数字,然后将整数数组中的每个项目转换为二进制。当用户键入“ c357”时,“ c”应转换为99,然后转换为二进制。然后,“ 357”也应转换为二进制。在main()函数中,strlen(convert)不能准确表示数组convert中的项数,因此只能迭代第一个数组项。

#include <stdio.h>
#include <stdlib.h>
#include <ctype.h>
#include <unistd.h>
#include <string.h>

#define EIGHT_BITS 255
#define SIXTEEN_BITS 65535
#define THIRTY_TWO_BITS 4294967295UL

//  DETERMINE NUMBER OF BITS TO OUTPUT
int getBitLength(unsigned long d) {
    int l;

    if (d <= EIGHT_BITS) {
        l = 8;
    }
    else if (d > EIGHT_BITS && d <= SIXTEEN_BITS) {
        l = 16;
    }
    else if (d > SIXTEEN_BITS && d <= THIRTY_TWO_BITS) {
        l = 32;
    }

    return l;
}

//  CONVERT INPUT TO BINARY VALUE
char* convertToBinary(unsigned long int decimal) {
    int l = getBitLength(decimal);
    static char b[33];
    char bin[33];
    int i, j, k = 0, r;

    b[33] = '\0';
    bin[33] = '\0';

    printf("Bits................ %ld\n", l);

    //  creates array
    for (i = 0; i < l; i++) {
        r = decimal % 2;
        decimal /= 2;
        b[i] = r;
    }

    //  reverses array for binary value
    for (j = l - 1; j >= 0; j--) {
        bin[k] = b[j];
        strncpy(&bin[k], &b[j], l);
        snprintf(&bin[k], l, "%d", b[j]);
        k++;
    }

    printf("Binary Value: %s\n", bin);

    return bin;
}

unsigned long int* numbersToConvert(char* input) {
    const int MAX_INPUT = 20;
    int i, k = 0, z = 0;
    char numbers[MAX_INPUT];
    unsigned long int *toConvert = malloc(MAX_INPUT * sizeof(int));

    numbers[MAX_INPUT] = '\0';

    for (i = 0; i < strlen(input); i++) {

        if (isdigit(input[i])) {
            numbers[z] = input[i];
            if (!isdigit(input[i + 1])) {
                toConvert[k] = strtol(numbers, NULL, 10);
                printf("----- %ld -----\n", toConvert[k]);
                z = 0;
            }
            else {
                z++;
            }
        }
        else {
            printf("----- %c -----\n", input[i]);
            printf("Character Code: %d\n", input[i]);

            toConvert[k] = (unsigned long int) input[i];
        }
        k++;
    }

    return toConvert;
}

int main(void) {
    const int MAX_INPUT = 20;
    int i, p;
    char input[MAX_INPUT];
    unsigned long int* convert;
    printf("------- Input --------\n");
    scanf("%s", input);

    input[MAX_INPUT] = '\0';
    //  PRINT INPUT AND SIZE
    printf("\nInput: %s\n", input);

    convert = numbersToConvert(input);
    convert[MAX_INPUT] = '\0';
    printf("strlen: %ld\n", strlen(convert));

    for (i = 0; i < strlen(convert); i++) {
        printf("num array: %ld\n", convert[i]);
        convertToBinary(convert[i]);
    }

    return 0;
}

我试图使每个字符串都终止以防止未定义的行为。我不确定某些变量(如果有)是否是静态的。

1 个答案:

答案 0 :(得分:0)

很难读取您的代码。

在这里您正在工作(将数字转换为二进制):

type ManyProps = 'name' | 'age' | 'height'

type MyObj = {[key in ManyProps]: number, name?: string}

https://godbolt.org/z/6sRC4C