Question

我有一个像这样的复杂JSON对象：

  {
    "item_detail": [
      {
        "itemid": "4702385896",
        "modelid": "8307307322",
        "quantity": "1"
      },
      {
        "itemid": "3902478595",
        "modelid": "8306561848",
        "quantity": "1"
      },
      {
        "itemid": "3409528897",
        "modelid": "10922686275",
        "quantity": "1"
      },
      {
        "itemid": "4702385896",
        "modelid": "8307307323",
        "quantity": "1"
      }
    ],
    "shopid": "128449080"
  },
  {
    "item_detail": [
      {
        "itemid": "7906381345",
        "modelid": "9745718882",
        "quantity": "1"
      },
      {
        "itemid": "6710792892",
        "modelid": "11474621623",
        "quantity": "1"
      }
    ],
    "shopid": "36121097"
  }
]

我正在努力将所有（itemid，shopid）提取到Presto中的行中。我想要的结果是：

itemid     | shopid
-----------+-------
4702385896 | 128449080
3902478595 | 128449080
3409528897 | 128449080
4702385896 | 128449080
7906381345 | 36121097
6710792892 | 36121097

我已经使用CROSS JOIN UNNEST和TRANSFORM来获得结果，但是没有运气。有人对此有解决方案吗？

非常感谢！

Answer 1

将json_extract与cast一起用于array和unnest，如下所示：

presto:default> SELECT
             ->  json_extract_scalar(item_detail, '$.itemid') itemid,
             ->  json_extract_scalar(shopping, '$.shopid') shopid
             -> FROM t
             -> CROSS JOIN UNNEST(CAST(my_json AS array(json))) AS x(shopping)
             -> CROSS JOIN UNNEST(CAST(json_extract(shopping, '$.item_detail') AS array(json))) AS y(item_detail)
             -> ;
             ->
   itemid   |  shopid
------------+-----------
 4702385896 | 128449080
 3902478595 | 128449080
 3409528897 | 128449080
 4702385896 | 128449080
 7906381345 | 36121097
 6710792892 | 36121097
(6 rows)

（在Presto 327上验证）

顺便说一句，如果任何数组可能为空或丢失，我建议使用LEFT JOIN UNNEST ... ON true而不是CROSS JOIN UNNEST（这需要像样的Presto版本）：

SELECT
 json_extract_scalar(item_detail, '$.itemid') itemid,
 json_extract_scalar(shopping, '$.shopid') shopid
FROM t
LEFT JOIN UNNEST(CAST(my_json AS array(json))) AS x(shopping) ON true
LEFT JOIN UNNEST(CAST(json_extract(shopping, '$.item_detail') AS array(json))) AS y(item_detail) ON true;

在Presto中提取复杂的嵌套JSON数组

1 个答案: