Question

我需要将对象类传递给方法（gson.fromJson）但JRuby说：'org.jruby.gen.InterfaceImpl624212141@187ef71' is not a Class

如何在JRuby中引用类（例如Bob.class）？

include Java 
include_class Java::com.google.gson.Gson
include_class Java::com.bobmanager.Bob

def json_load(filename)
  gson = Gson.new
  jsonBob = IO.read filename
  $dto = gson.fromJson jsonBob, Bob.class  # <-- here is the problem: Bob.class  
end

json_load 'C:/json/1152.json'

产生以下内容：

<stack_trace_array message='org.jruby.embed.EvalFailedException: Native Exception: 'class java.lang.IllegalArgumentException'; Message: Type 'org.jruby.gen.InterfaceImpl624212141@187ef71' is not a Class, ParameterizedType, or GenericArrayType. Can't extract class.; StackTrace: java.lang.IllegalArgumentException: Type 'org.jruby.gen.InterfaceImpl624212141@187ef71' is not a Class, ParameterizedType, or GenericArrayType. Can't extract class.
    at com.google.gson.TypeUtils.toRawClass(TypeUtils.java:83)
    at com.google.gson.TypeInfo.<init>(TypeInfo.java:34)
    at com.google.gson.ObjectNavigator.accept(ObjectNavigator.java:102)
    at com.google.gson.JsonDeserializationContextDefault.fromJsonObject(JsonDeserializationContextDefault.java:73)
    at com.google.gson.JsonDeserializationContextDefault.deserialize(JsonDeserializationContextDefault.java:51)
    at com.google.gson.Gson.fromJson(Gson.java:568)
    at com.google.gson.Gson.fromJson(Gson.java:515)
    at com.google.gson.Gson.fromJson(Gson.java:484)
    at com.google.gson.Gson.fromJson(Gson.java:434)
' >

Answer 1

尝试使用Bob.java_class而不是Bob.class

如何在JRuby中引用Class对象？

1 个答案: