Question

实际上，我正在尝试将API JSON数据填充到tableView中，但是不能将enum用作字符串。

struct Results: Codable {
    let container_id : Int?
    let container_number : String?
    let shipment_id : Int?
    let bill_of_lading : BillOfLading
    let eta : String?
    let discharge_port_id : Int?
    let discharge_port_name : String?
    let consignee_id : Int?
    let consignee_name : String?
    let customer_id : Int?
    let customer_name : String?
    let shipment_status : String?
    let container_status : String?
    let user_id : Int?
    let user_display_name : String?
    let commodities : [Commodities]
    let all_sold : Bool?
    let quantities : Quantities
    let sales : [String]?
    let sales_report : Sales_report
    let commodities_summary : String?
    let commodity_quantity_summary : String?
    let commodities_summary_en : String?
    let commodity_quantity_summary_en : String?
}

enum BillOfLading: Codable {
    case integer(Int)
    case string(String)

    init(from decoder: Decoder) throws {
        let container = try decoder.singleValueContainer()
        if let x = try? container.decode(Int.self) {
            self = .integer(x)
            return
        }
        if let x = try? container.decode(String.self) {
            self = .string(x)
            return
        }
        throw DecodingError.typeMismatch(BillOfLading.self, DecodingError.Context(codingPath: decoder.codingPath, debugDescription: "Wrong type for BillOfLading"))
    }

    func encode(to encoder: Encoder) throws {
        var container = encoder.singleValueContainer()
        switch self {
        case .integer(let x):
            try container.encode(x)
        case .string(let x):
            try container.encode(x)
        }
    }
}

Answer 1

您可以定义一个计算属性，例如

extension BillOfLading {
    var stringValue: String {
        switch self {
            case .integer(let value): return String(value)
            case .string(let value): return value
        }
    }
}

那你就可以做

cell.bolLabel.text = data.bill_of_lading.stringValue

Answer 2

您正在使用cell.bolLable.text = dataa.bill_of_lading 其中bill_of_lading是BillOfLading类型，和bolLable.text仅接受字符串类型。

尝试cell.bolLable.text = dataa.bill_of_lading.string

Answer 3

这是一种对我来说很好的解决方法

// MARK: - Imagefile
struct Imagefile : Codable
{
let large, thumb: String?
let pageName: String?
let pageKey: BookType?

enum CodingKeys: String, CodingKey {
    case large, thumb
    case pageName = "page_name"
    case pageKey = "page_key"
    }
}

enum BookType: Codable {
case int(Int)
case string(String)
init(from decoder: Decoder) throws {
    let container = try decoder.singleValueContainer()
    if let x = try? container.decode(Int.self) {
        self = .int(x)
        return
    }
    if let x = try? container.decode(String.self) {
        self = .string(x)
        return
    }
    throw DecodingError.typeMismatch(BookType.self, DecodingError.Context(codingPath: decoder.codingPath, debugDescription: "Wrong type for BookType"))
}
func encode(to encoder: Encoder) throws {
    var container = encoder.singleValueContainer()
    switch self {
    case .int(let x):
        try container.encode(x)
    case .string(let x):
        try container.encode(x)
    }
}

}

我在这里使用BookType。

如何使用枚举获取字符串值

3 个答案: