我有一个简单的表单,其中包含一些文本输入,并使用该表单上传照片。存储方法效果很好,但是我在更新方法中做错了。
这是我的存储方法,效果很好:
public function store(Request $request)
{
dd($request);
$post = new Post;
$post->title = $request->title;
$post->user_id = $request->user()->id;
$post->who = $request->who;
$post->when = $request->when;
$post->where = $request->where;
$post->body_text = $request->body;
$post->embed = $request->embed;
$post->status = "4";
$post->tags = $request->tags;
$post->slug = "asdasd";
$post->ip = request()->ip();
if($request->hasfile('photo'))
{
foreach($request->file('photo') as $image)
{
$name= time()."".$this->photo_san($image->getClientOriginalName());
$image->move(public_path().'/uploads/', $name);
$data[] = $name;
}
$post->photo = json_encode($data);
}
$post->save();
$post->slug = $post->id."-".$this->make_slug($request->title);
$post->save();
Session::flash('success', 'Well done.');
return redirect()->route('archive');
}
这是我的更新方法,可以保存除照片以外的所有内容:
public function update(Request $request, $id)
{
if(Auth::user()->role == 3 || Auth::user()->id == Post::find($id)->user_id){
$post = Post::find($id);
$post->title = $request->title;
$post->user_id = $request->user()->id;
$post->who = $request->who;
$post->when = $request->when;
$post->where = $request->where;
$post->body_text = $request->body;
$post->embed = $request->embed;
$post->status = "4";
$post->tags = $request->tags;
$post->slug = $id."-".$this->make_slug($request->title);
$post->ip = request()->ip();
if($request->hasFile('photo'))
{
foreach($request->file('photo') as $image)
{
$name= time()."-edit-".$this->photo_san($image->getClientOriginalName());
$image->move(public_path().'/uploads/', $name);
$data[] = $name;
}
$post->photo = json_encode($data);
}
$post->save();
Session::flash('success', 'Well done.');
return redirect()->route('new');
}
else
Session::flash('error', 'Shame on you :( ');
return redirect()->route('new');
}
当我更新任何帖子时,所有内容都在更新,除了照片,我不知道出了什么问题。 我不知道是否有所不同,但我使用的是Laravel 5,8