值

Question

我有两列，说值列有像'abc|comp|science|raja'这样的记录，我想像abc,comp,science,raja那样分割这些记录，我需要将它与另一列说成CHECKER进行比较已有科学记录

值

abc|comp|science|raja

跳棋

science

Answer 1

您不需要分割字符串，甚至不需要正则表达式；只需检查checker字符串（带后跟定界符）是否是value的子字符串（带前导和尾随定界符）：

Oracle设置：

CREATE TABLE your_table ( value, checker ) as
  SELECT 'abc|comp|science|raja', 'science' FROM DUAL UNION ALL
  SELECT 'abc|def|ghi',           'xyz'     FROM DUAL UNION ALL
  SELECT 'abc',                   'abc'     FROM DUAL UNION ALL
  SELECT 'abcdef',                'abc'     FROM DUAL

查询：

SELECT *
FROM   your_table
WHERE  '|' || value || '|' LIKE '%|' || checker || '|%';

输出：

VALUE                 | CHECKER
:-------------------- | :------
abc|comp|science|raja | science
abc                   | abc

db <>提琴here

Answer 2

您可以将管道分隔的字符串拆分为各个值，并将其表示为表格。然后，您可以加入Checkers表。网络上到处都是示例，有两种实现方法。

REGEXP方式...

WITH test_tab AS 
(SELECT 'abc|comp|science|raja' str FROM dual  
)  
SELECT regexp_substr (str, '[^|]+', 1, rownum) split  
  FROM test_tab  
CONNECT BY LEVEL <= LENGTH (regexp_replace (str, '[^|]+'))  + 1;

如果数据库中有Application Express，则可以使用apex_string为您做魔术：

SELECT
  column_value
  FROM
  TABLE(apex_string.split(
    'abc|comp|science|raja',
    '|'
  ));

Answer 3

这里是一个选择：

SQL> with test (id, value, checkers) as
  2    (select 1, 'abc|comp|science|raja', 'science' from dual union all
  3     select 2, 'xyz|bla|nothing'      , 'zzz'     from dual
  4    )
  5  select t.id,
  6         regexp_substr(t.value, '[^\|]+', 1, column_value) val,
  7         column_value rn,
  8         t.checkers,
  9         --
 10         case when regexp_substr(t.value, '[^\|]+', 1, column_value) = t.checkers then 'Match'
 11              else 'No match'
 12         end what
 13  from test t cross join table(cast(multiset(select level from dual
 14                                             connect by level <= regexp_count(t.value, '\|') + 1
 15                                            ) as sys.odcinumberlist))
 16  order by t.id, rn;

        ID VAL                           RN CHECKER WHAT
---------- --------------------- ---------- ------- --------
         1 abc                            1 science No match
         1 comp                           2 science No match
         1 science                        3 science Match
         1 raja                           4 science No match
         2 xyz                            1 zzz     No match
         2 bla                            2 zzz     No match
         2 nothing                        3 zzz     No match

7 rows selected.

SQL>

Answer 4

听起来您只想检查检查器是否在值中，在这种情况下，您可以执行以下操作：

    with mytable as 
( select 'abc|comp|science|raja' value
       , 'science' as checker
    from dual
   union all
  select 'science|abc|comp|raja'
       , 'science'
    from dual
   union all
  select 'abc|comp|raja|science'
       , 'science'
    from dual )
select x.value
  from mytable x
 where regexp_like(value, '(^|\|)' || checker || '($|\|)')

regex_like正在使用管道或字符串结尾在检查程序的值中进行搜索，因此它将与字符串的开头，中间或结尾处的关键字匹配。但这与“科学”不符。

或者，如果您想查看所有行并检查它们是否通过了“检查”，则可以执行以下操作：

    with mytable as 
( select 'abc|comp|science|raja' value
       , 'science' as checker
    from dual
   union all
  select 'science|abc|comp|raja'
       , 'science'
    from dual
   union all
  select 'abc|comp|raja|science'
       , 'science'
    from dual
   union all
  select 'abc|comp|raja|sciences'
       , 'science'
    from dual )
select x.value
     , x.checker
     , case when regexp_substr(value, '(^|\|)' || checker || '($|\|)') is not null 
            then 'Y' 
        end as passed
  from mytable x

拆分具有以下内容的记录：分隔符

值

跳棋

4 个答案: