df[['uid','verified','is_duplicate']].head(2)
如何仅获取is_duplicate=False
uid verified is_duplicate
0 2355954 True True
1 2626002 True False
答案 0 :(得分:1)
只需创建一个蒙版:
df = df[['uid','verified','is_duplicate']].head(2)
df = [~df.is_duplicate]
答案 1 :(得分:1)
由于值已经是布尔值,因此您可以取反条件:
df[~df.is_duplicate]
哪个给:
uid verified is_duplicate
1 2626002 True False