我已在此处针对此帖子实施了我的服务器应用程序:http://www.codeguru.com/csharp/csharp/cs_network/sockets/article.php/c8781#Client1
总结:我正在使用异步套接字ala BeginAccept(..),BeginReceive(..)。 我的服务器能够处理多个客户端,一切正常,直到客户端执行两个或多个同步发送操作,而无需等待一段时间。客户端没有收到任何错误,因此没有得到通知,服务器没有收到第二条消息!如果客户等待约。第一次发送操作后100ms,一切正常。 我认为当我使用TCP时,我可以确保服务器收到消息。 (除了抛出异常)! 你能帮我解决一下吗?
这是WaitForData(..)& OnDataReceive(..)我在服务器中实现的方法
public void WaitForData(MyClient client)
{
try
{
if (pfnCallBack == null)
{
pfnCallBack = new AsyncCallback(OnDataReceived);
}
iarResult = client.Socket.BeginReceive(client.DataBuffer,
0, client.DataBuffer.Length,
SocketFlags.None,
pfnCallBack,
client);
}
catch (SocketException se)
{
MessageBox.Show("SocketException@WaitForData" + se.Message);
}
}
public void OnDataReceived(IAsyncResult asyn)
{
try
{
MyClient user= (MyClient)asyn.AsyncState;
int iRx = user.Socket.EndReceive(asyn);
byte[] receivedData = user.DataBuffer;
MemoryStream memStream = new MemoryStream();
BinaryFormatter binForm = new BinaryFormatter();
memStream.Write(receivedData, 0, receivedData.Length);
memStream.Seek(0, SeekOrigin.Begin);
MyMessage msg = (MyMessage)binForm.Deserialize(memStream);
switch (msg.Command)
{
case (MyMessage.MyCommand.ConnId):
this.connId = (int) msg.MyObject;
tsslConnStatus.Text += " | ID: " + connId.ToString();
break;
case (MyMessage.MyCommand.Text):
MessageBox.Show(msg.MyObject.ToString());
break;
}
WaitForData(server);
}
catch (ObjectDisposedException ode)
{
MessageBox.Show("ObjectDisposedException@OnReceiveData" + ode.Message);
}
catch (SocketException se)
{
MessageBox.Show("SocketException@OnReceiveData" + se.Message);
}
}
CLIENT调用同步SEND METHOD TWICE或更多!服务器INSTANCEOF MyClient
if (server.Socket.Connected)
{
BinaryFormatter bf = new BinaryFormatter();
MemoryStream ms = new MemoryStream();
bf.Serialize(ms, message);
MyMessage = new MyMessage(something);
server.Socket.Send(ms.ToArray());
}
所以,我认为这段代码片段必须足以让你得到我想要使用的想法! 如果您需要更多详细信息或代码片段,请告诉我我会发布它!
感谢名单!
答案 0 :(得分:12)
TCP是基于流的,而不是基于消息的。一个Read
可以包含以下任何替代方案:
因此,您需要使用某种方法来查看是否已收到完整的消息。最常见的方法是:
简单示例只有标题长度。
服务器端:
var buffer = binaryFormmater.Serialize(myobj);
var length = buffer.Length;
networkStream.Send(length);
networkStream.Send(buffer, 0, buffer.Length);
客户方:
var header = new buffer[4];
// TODO: You need to make sure that 4 bytes have been read.
networkStream.Read(header, 0, 4);
var length = BitConverter.ToInt32(buffer);
var readbuffer= new byte[65535];
var bytesLeft = length;
var messageStream = new MemoryStream();
while (bytesLeft > 0)
{
var read = networkStream.Read(readbuffer, 0, bytesLeft);
messageStream.Write(readbuffer, 0, read);
bytesLeft -= read,
}
messageStream.Seek(0, SeekOrigin.Begin);
MyMessage msg = (MyMessage)binForm.Deserialize(messageStream);