Question

当我尝试向服务器发送请求时，无论是否设置setRequestMethod（“ GET”），服务器都只会收到POST请求。这是我正在调用的函数，带有一个URL和两个我需要与它们一起发送的参数：

const [name, setName] = useState([]);
    const message = ["C", "h", "a", "s", "e", " ", "L", "i", "p", "s", "c", "o", "m", "b", " ", "W", "e", "b", " ", "D", "e", "v", "e", "l", "o", "p", "e", "r"]
    let letter = "";
    const displayName = () => {
        for(var i = 0; i<message.length; i++) {
            letter += message[i];
            console.log(letter)
            setName(letter);
            setTimeout(function(){console.log("work");}, 1000)
        }
    }
    useEffect(() => {
        displayName();
      }, []);

欢迎任何帮助，或者通过发送URL和两个参数来向服务器发送GET请求的任何其他功能。

Answer 1

执行以下操作：

import java.io.BufferedReader;
import java.io.InputStream;
import java.io.InputStreamReader;
import java.net.HttpURLConnection;
import java.net.URL;

class Main {
    public static void main(String[] args) {
        System.out.println(getHTML("http://localhost:8080/TestDynamicProject/getdata.do?t1=tp1&t2=tp2"));
    }

    public static String getHTML(String urlToRead) {
        try {
            StringBuilder result = new StringBuilder();
            InputStream stream = null;
            URL url = new URL(urlToRead);
            HttpURLConnection conn = (HttpURLConnection) url.openConnection();
            conn.setRequestMethod("GET");
            conn.connect();
            if (conn.getResponseCode() == HttpURLConnection.HTTP_OK) {
                stream = conn.getInputStream();
            }

            BufferedReader rd = new BufferedReader(new InputStreamReader(conn.getInputStream()));
            String line;
            while ((line = rd.readLine()) != null) {
                result.append(line);
            }

            rd.close();
            return result.toString();
        } catch (Exception e) {
            return e.getMessage().toString();
        }
    }
}

输出：

Response from GET | Request parameters: t1=[tp1],t2=[tp2]

以下是我的Servlet：

@WebServlet("/getdata.do")
public class TestServlet extends HttpServlet {

    public TestServlet() {
    }

    protected void doGet(HttpServletRequest request, HttpServletResponse response)
            throws ServletException, IOException {
        StringBuilder sb = new StringBuilder();
        request.getParameterMap().forEach((k, v) -> sb.append(k.toString() + "=" + Arrays.toString(v) + ","));
        sb.deleteCharAt(sb.length() - 1);
        response.getWriter().append("Response from GET").append(" | Request parameters: ").append(sb);
    }

    protected void doPost(HttpServletRequest request, HttpServletResponse response)
            throws ServletException, IOException {
        response.getWriter().append("Response from POST");
    }
}

使用application / x-www-form-urlencoded格式在Java应用程序中获取请求

1 个答案: