如何将fetchAll()
结果转换为字符串?就像遍历所有获取的数组内容并尝试回显它们一样,这给了我一个“数组到字符串转换”错误。
我想回显数组的每个值。
$pdo = new PDO($dsn, $user, $password);
$pdo->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
$stmt = $pdo->prepare("SELECT company_name, job_name, job_description, job_location, contact_email FROM joblist");
$stmt->execute();
$result = $stmt->fetchAll();
print_r($result);
// echo $result[0];
foreach ($result as $key => $value) {
echo $value;
}
我的结果如下:
Array (
[company_name] => alex
[0] => alex
[job_name] => driver
[1] => driver
[job_description] => drive a truck with goods
[2] => drive a truck with goods
[job_location] => america
[3] => america
[contact_email] => alex@email.com
[4] => alex@email.com
)
注意:数组到字符串的转换
C:\xampp\htdocs\jobs-app\postjob.php
在第23行
答案 0 :(得分:1)
$ value是数组格式。因此您无法回显数组。
foreach ($result as $key => $value) {
echo $value['job_name'];
}
答案 1 :(得分:1)
您在数组中有一个数组,像这样回显它应该起作用
foreach ($result as $key => $value) {
echo $value[0];
}
如果要使其更加精确,则应执行此操作
foreach ($result as $key => $value) {
echo $value['company_name'];
}
答案 2 :(得分:0)
$ value是数组。试试这个。
foreach ($result as $key => $value) {
echo $value['company_name'];
}