Question

让我解释一下我的问题。
在mysql中，我有一个像这样的订单表（简化）：

+------------+-------+
| customerID | price | 
+------------+-------+
| 10         | 10    |
| 20         | 10    |
| 20         | 10    |
| 30         | 10    |
| 30         | 10    |
| 30         | 10    |
| 120        | 10    |
| 120        | 10    |
| 130        | 10    |
| 130        | 10    |
| 130        | 10    |
| 130        | 10    |
+------------+-------+

我想要按总价的订单数来吸引客户。

+-----------------------------+--------------------+-------------+  
| number_of_order_by_customer | number_of_customer | total_price |  
+-----------------------------+--------------------+-------------+  
| 1                           | 1                  | 10          |  
| 2                           | 2                  | 40          |  
| 3 and more                  | 2                  | 70          |  
+-----------------------------+--------------------+-------------+

我们可以像这样读取该表：
-1位客户订购10次，每次10欧元（客户10）
-2位客户订购2次，总计40欧元（20位客户和120位客户）
-2位客户订购3次或以上，总计70欧元（客户30次（3次）和客户130次（4次））

我的问题是“ 3个以上” 有了这个请求，我可以有1,2,3,4次，但我不知道如何分组3次和4次

SELECT 
    number_of_order_by_customer, COUNT(number_of_order_by_customer) AS number_of_customer, SUM(price) AS total_price 
FROM
(
    SELECT
        COUNT(o.customerID ) AS number_of_order_by_customer, sum(o.price ) AS price
    FROM 
        order o
    GROUP BY o.customerID 
) AS tmp

GROUP BY number_of_order_by_customer
;

我明白了：

+-----------------------------+--------------------+-------------+  
| number_of_order_by_customer | number_of_customer | total_price |  
+-----------------------------+--------------------+-------------+  
| 1                           | 1                  | 10          |  
| 2                           | 2                  | 40          |  
| 3                           | 1                  | 30          |  
| 4                           | 1                  | 40          |
+-----------------------------+--------------------+-------------+

有人知道如何在同一请求中获得“ 3个及更多”吗？

Answer 1

表达时的用例-

SELECT 
    case when number_of_order_by_customer>=3 then '3 or More' else cast(number_of_order_by_customer as varchar(10)) end as number_of_order_by_customer, COUNT(nb) AS number_of_customer, SUM(price) AS total_price 
FROM
(
    SELECT
        COUNT(o.customerID ) AS number_of_order_by_customer, sum(o.price ) AS price
    FROM 
        order o
    GROUP BY o.customerID 
) AS tmp

GROUP BY case when number_of_order_by_customer>=3 then '3 or More' else cast(number_of_order_by_customer as varchar(10)) end

大于X的MYSQL分组依据

1 个答案: