如何从作为lambda传递的功能接口对象的实例中获取参数？

Question

@FunctionalInterface
public interface ServiceCaller {
    void callService();
}

//common method to execute any service call
public void executeService(ServiceCaller serviceCaller) {
    //do common things
    //i want to access dbValidationRequest/apiValidationRequest here for logging purpose
    try {
        serviceCaller.callService();
    } catch (Exception ex) {
        //do common things
        LogUtils.log(logger, ex);
    }
    //do common things
}

//my clients call this
public void validateFromDb(DbValidationRequest dbValidationRequest){
    commonUtils.executeService(()-> dbValidationService.validate(dbValidationRequest));
}

//my clients call this
public void validateFromApi(ApiValidationRequest apiValidationRequest){
    commonUtils.executeService(()-> apiValidationService.validate(apiValidationRequest));
}

这是Java Spring Application的控制器。在 executeService 方法内部，我传递了 ServiceCaller 接口的实例。我使用此方法从控制器调用所有服务。如果我使用智能IDEA进行评估，则可以在executeService方法内部查看dbValidationRequest / apiValidationRequest的值（如arg $ 2，请参见附图）。我需要打印这些对象以用于记录目的，我也根本不想使用方面。我怎样才能做到这一点。如果智能IDEA可以看到这些值，为什么不能以编程方式进行？

Answer 1

arg$1和arg$2可以视为类的字段，因此可以通过反射获得。

    String var1 = "Content Var 1";
    String var2 = "Content Var 2";

    Supplier<String> stringSupplier = () -> var1 + var2;

    Field[] declaredFields = stringSupplier.getClass().getDeclaredFields();

    for (Field f : declaredFields) {
        f.setAccessible(true);
        System.out.println(
            "Field Name: " + f.getName() +
            ", value: " + f.get(stringSupplier)
        );
    }

    // Field Name: arg$1, value: Content Var 1
    // Field Name: arg$2, value: Content Var 2