我正在发现Combine。我编写了以“组合”方式发出HTTP请求的方法,例如:
func testRawDataTaskPublisher(for url: URL) -> AnyPublisher<Data, Error> {
var request = URLRequest(url: url,
cachePolicy: .useProtocolCachePolicy,
timeoutInterval: 15)
request.httpMethod = "GET"
return urlSession.dataTaskPublisher(for: request)
.tryMap {
return $0.data
}
.eraseToAnyPublisher()
}
我想多次调用该方法并完成一个任务,例如:
let myURLs: [URL] = ...
for url in myURLs {
let cancellable = testRawDataTaskPublisher(for: url)
.sink(receiveCompletion: { _ in }) { data in
// save the data...
}
}
上面的代码不起作用,因为我必须将cancellable存储在属于该类的变量中。
第一个问题是:将许多(例如1000个)可取消存储在诸如Set<AnyCancellable>
之类的东西中是个好主意吗?会不会导致内存泄漏?
var cancellables = Set<AnyCancellable>()
...
let cancellable = ...
cancellables.insert(cancellable) // ???
第二个问题是:所有可取消操作完成后如何启动任务?我在想类似的东西
class Test {
var cancellables = Set<AnyCancellable>()
func run() {
// show a loader
let cancellable = runDownloads()
.receive(on: RunLoop.main)
.sink(receiveCompletion: { _ in }) { _ in
// hide the loader
}
cancellables.insert(cancellable)
}
func runDownloads() -> AnyPublisher<Bool, Error> {
let myURLs: [URL] = ...
return Future<Bool, Error> { promise in
let numberOfURLs = myURLS.count
var numberOfFinishedTasks = 0
for url in myURLs {
let cancellable = testRawDataTaskPublisher(for: url)
.sink(receiveCompletion: { _ in }) { data in
// save the data...
numberOfFinishedTasks += 1
if numberOfFinishedTasks >= numberOfURLs {
promise(.success(true))
}
}
cancellables.insert(cancellable)
}
}.eraseToAnyPublisher()
}
func testRawDataTaskPublisher(for url: URL) -> AnyPublisher<Data, Error> {
...
}
}
通常,我会使用DispatchGroup
,启动多个HTTP任务并在任务完成时使用通知,但是我想知道如何使用Combine以现代的方式编写代码。
答案 0 :(得分:4)
通过创建发布者集合,应用flatMap
运算符,然后应用collect
等待所有发布者完成,然后才能继续运行,可以并行运行某些操作。这是您可以在游乐场中运行的示例:
import Combine
import Foundation
func delayedPublisher<Value>(_ value: Value, delay after: Double) -> AnyPublisher<Value, Never> {
let p = PassthroughSubject<Value, Never>()
DispatchQueue.main.asyncAfter(deadline: .now() + after) {
p.send(value)
p.send(completion: .finished)
}
return p.eraseToAnyPublisher()
}
let myPublishers = [1,2,3]
.map{ delayedPublisher($0, delay: 1 / Double($0)).print("\($0)").eraseToAnyPublisher() }
let cancel = myPublishers
.publisher
.flatMap { $0 }
.collect()
.sink { result in
print("result:", result)
}
以下是输出:
1: receive subscription: (PassthroughSubject)
1: request unlimited
2: receive subscription: (PassthroughSubject)
2: request unlimited
3: receive subscription: (PassthroughSubject)
3: request unlimited
3: receive value: (3)
3: receive finished
2: receive value: (2)
2: receive finished
1: receive value: (1)
1: receive finished
result: [3, 2, 1]
请注意,所有发布者都将立即开始(以其原始顺序)。
1 / $0
的延迟导致第一个发布者花费了最长的时间才能完成。请注意最后的值顺序。由于第一个完成时间最长,因此它是最后一个。