我试图制作一个game子手游戏,它从单词的文本文件中选择一个随机单词。然后以星号显示该单词,并要求用户猜出单词的每个字母(如果猜对了),并发现该字母,然后继续播放直到猜到单词中的所有字母。猜出单词后将显示数字错过,问他们是否想再次比赛。
我遇到的问题是,正确猜出该单词时,即使发现该单词,它也会不断要求输入字母。我不确定如何解决此问题。我想尽可能不使用linq来执行此操作。 任何帮助都会被
static void Main(string[] args)
{
char[] guessed = new char[26];
char guess = ' ';
char playAgain= ' ';
bool validLetterInput = false;
bool validAnswer = false;
int amountMissed = 0, index = 0;
do
{
// initilization of word and testword so that we could generate a testword with the same length as original
char[] word = RandomLine().Trim().ToCharArray();
char[] testword = new string('*', word.Length).ToCharArray();
char[] copy = word;
Console.WriteLine(testword);
Console.WriteLine("I have picked a random word on animals");
Console.WriteLine("Your task is to guess the correct word");
//Check if the 2 arrays are equal
while (testword != word)
{
while (!validLetterInput)
{
try
{
Console.Write("Please enter a letter to guess: ");
guess = char.Parse(Console.ReadLine().ToLower());
//Checks if guess is letter or not
if (((guess >= 'A' && guess <= 'Z') || (guess >= 'a' && guess <= 'z')))
{
validLetterInput = true;
}
else
{
Console.WriteLine("Invalid Input");
}
}
catch (Exception e)
{
Console.WriteLine(e.Message);
}
}
validLetterInput = false;
bool right = false;
for (int j = 0; j < copy.Length; j++)
{
if (copy[j] == guess)
{
Console.WriteLine("Your guess is correct.");
testword[j] = guess;
guessed[index] = guess;
index++;
right = true;
}
}
if (right != true)
{
Console.WriteLine("Your guess is incorrect.");
amountMissed++;
}
else
{
right = false;
}
Console.WriteLine(testword);
}
Console.WriteLine($"The word is {string.Join("",testword)}. You missed {amountMissed} times.");
while (!validAnswer)
{
try
{
Console.WriteLine("Do you want to guess another word? Enter y or n: ");
playAgain = char.Parse(Console.ReadLine());
if(playAgain == 'y' || playAgain == 'Y' || playAgain == 'n' || playAgain == 'N')
{
validAnswer = true;
}
else
{
Console.WriteLine("Invalid input try again");
}
}
catch (Exception e)
{
Console.WriteLine(e.Message);
}
}
validAnswer = false;
} while (playAgain == 'y' || playAgain == 'Y');
Console.WriteLine("Good-Bye and thanks for playing my Hangman game.");
}
public static string RandomLine()
{
// store text file in an array and return a random value
string[] lines = File.ReadAllLines("E:\\Amimals1.csv");
Random rand = new Random();
return lines[rand.Next(lines.Length)].ToLower();
}
}
答案 0 :(得分:0)
有多种比较两个数组/列表的方法。我看到的用于字符数组/列表的简单方法是将它们转换为字符串,然后进行比较。
Array Comparison thread on stackoverflow
testword.ToString() != word.ToString()
关于Flydog57,使用this link学习如何调试代码:
答案 1 :(得分:0)
使用“ SequenceEqual”而不是!=比较数组。这样,您将需要将while语句更改为:
while (!testword.SequenceEqual(word))
Quartermeister对此进行了说明,ohn Buchanan在问题“在C#中比较数组的最简单方法”中作了进一步解释。链接在这里:
Easiest way to compare arrays in C#
否则很棒的程序!
请注意,当您尝试调试时,我想输入的一个简单内容是,如果我无法通过调试弄清楚,我最初希望看到什么响应。您以后可以随时删除该行。我将此放在while语句的末尾。
Console.WriteLine(testword.SequenceEqual(word));