Question

我在React和Apollo中使用graphql：generate从graphql模式创建类型。

我还在使用react-apollo-hooks useQuery输出数据。

一切似乎都正常，我可以看到输出的数据

我的问题是我看不到如何声明生成的类型，然后在vc代码中获取intelliSense。

查询

import { gql } from 'apollo-boost';

export const GET_ALL_RECIPES = gql`

  query RecipesData{
    recipe{
      _id
      name
      description
    }
  }
`

生成的类型

/* tslint:disable */
/* eslint-disable */
// This file was automatically generated and should not be edited.

// ====================================================
// GraphQL query operation: RecipesData
// ====================================================

export interface RecipesData_recipe {
  __typename: "Recipe";
  _id: string | null;
  name: string | null;
  description: string | null;
}

export interface RecipesData {
  recipe: (RecipesData_recipe | null)[] | null;
}

App.tsx

import React from 'react';
import './App.css';

import { useQuery } from 'react-apollo-hooks';
import { GET_ALL_RECIPES } from '../queries';

import { RecipesData_recipe } from '../generated/RecipesData';

const App: React.FC<RecipesData> = () => {

  const { data, loading } = useQuery(GET_ALL_RECIPES, {
    suspend: false
  })

  if (loading || !data) return <div>Loading</div>

  return (
    <ul>
      {data.recipe.map((recipe) =>
        <li key={recipe._id}>{recipe.name}</li>
      )}
    </ul>
  );
}

export default App;

我如何正确地在App.tsx中声明RecipesData或RecipesData_recipe以对recipe.name使用intelliSense

React，Graphql模式类型声明

0 个答案: