我有一个名为productCheck的数据框:
prod <- c("GAS","GAS","GLP","GLP","GNV")
monthYear <- c("2016-06-01","2016-07-01","2016-06-01","2016-07-01","2016-07-01")
meanValue <- c(3,5,8,1,6)
price <- c(0,0,0,0,0)
productCheck <- data.frame(prod,monthYear,meanValue,price)
productCheck$prod <- as.factor(productCheck$prod)
productCheck$monthYear <- as.factor(productCheck$monthYear)
执行以下循环时,出现错误:
for (j in levels(productCheck$prod))
{
firstPeriod <- NA
for (k in levels(productCheck$monthYear))
{
if (!is.na(firstPeriod))
{
secondPeriod <- k
productCheck[productCheck$monthYear==j & productCheck$prod==secondPeriod,]$price <-
100*(productCheck[productCheck$monthYear==secondPeriod & productCheck$prod==j,]$meanValue -
productCheck[productCheck$monthYear==firstPeriod & productCheck$prod==j ,]$meanValue) /
productCheck[productCheck$monthYear==firstPeriod & productCheck$prod==j ,]$meanValue
}
firstPeriod <- k
}
}
$<-.data.frame
(*tmp*
,“价格”,值=数字(0))中的错误:替换有0行,数据有1
问题是,对于GNV产品,没有“ 2016-06-01”期间的信息。如何避免此错误?
答案 0 :(得分:1)
正如您所显示的,我认为您的代码不必要太长,无法进行for循环和问题。我可以看到几种替代方法,其中一种是:
library(tidyverse)
productCheck %>%
pivot_wider(names_from =monthYear, values_from = meanValue) %>%
mutate(price = 100*(`2016-07-01` - `2016-06-01`)/`2016-06-01`)
# A tibble: 3 x 4
prod price `2016-06-01` `2016-07-01`
<fct> <dbl> <dbl> <dbl>
1 GAS 66.7 3 5
2 GLP -87.5 8 1
3 GNV NA NA 6
您的原始数据:
prod <- c("GAS", "GAS", "GLP", "GLP", "GNV")
monthYear <- c("2016-06-01", "2016-07-01", "2016-06-01", "2016-07-01", "2016-07-01")
meanValue <- c(3, 5, 8, 1, 6)
productCheck <- data.frame(prod, monthYear, meanValue)