我的问题:如果用户在表视图单元格中按下按钮,我想打开某种Profil。单元数据是从Parse下载的。
这个想法是基于Instagram的,如果您单击Insta上的用户名按钮,则会打开发布该图像的用户的个人资料。我想创建相同的代码,但是我无法创建代码来获取用户。你能帮我吗?
这里有一些代码:
import UIKit
import Parse
class HomeController: UIViewController, UITableViewDelegate, UITableViewDataSource {
private let reuseIdentifer = "FeedCell"
var delegate: HomeControllerDelegate?
var newCenterController: UIViewController!
let tableView = UITableView()
//Für Parse:
var users = [String: String]()
var comments = [String]()
var usernames = [String]()
var lastnames = [String]()
var imageFiles = [PFFileObject]()
var wischen: UISwipeGestureRecognizer!
var wischen2: UISwipeGestureRecognizer!
override func viewDidLoad() {
super.viewDidLoad()
view.backgroundColor = .white
getData()
configureNavigationBar()
configurateTableView()
wischen = UISwipeGestureRecognizer()
wischen.addTarget(self, action: #selector(handleMenuToggle))
wischen.direction = .right
wischen.numberOfTouchesRequired = 1
view.addGestureRecognizer(wischen)
wischen2 = UISwipeGestureRecognizer()
wischen2.addTarget(self, action: #selector(handleMenuToggle))
wischen2.direction = .left
wischen2.numberOfTouchesRequired = 1
view.addGestureRecognizer(wischen2)
}
@objc func handleMenuToggle() {
delegate?.handleMenuToggle(forMenuOption: nil)
}
@objc func showProfile() {
let vc: AProfileViewController!
vc = AProfileViewController()
vc.modalPresentationStyle = .fullScreen
present(vc, animated: true)
}
func configureNavigationBar() {
navigationController?.navigationBar.barTintColor = .darkGray
navigationController?.navigationBar.barStyle = .black
navigationController?.navigationBar.titleTextAttributes = [NSAttributedString.Key.font: UIFont(name: "Noteworthy", size: 22)!, NSAttributedString.Key.foregroundColor: UIColor.white]
//navigationController?.navigationBar.titleTextAttributes = [NSAttributedString.Key.foregroundColor: UIColor.white]
navigationItem.title = "Mobile Job Board"
navigationItem.leftBarButtonItem = UIBarButtonItem(image: #imageLiteral(resourceName: "ic_menu_white_3x").withRenderingMode(.alwaysOriginal), style: .plain, target: self, action: #selector(handleMenuToggle))
navigationItem.rightBarButtonItem = UIBarButtonItem(image: #imageLiteral(resourceName: "ic_mail_outline_white_2x").withRenderingMode(.alwaysOriginal), style: .plain, target: self, action: #selector(showCreateNewArticle))
}
//MARK: Table View
//skiped table view configuration
}
// - MARK: Table view data source
func numberOfSections(in tableView: UITableView) -> Int {
// #warning Incomplete implementation, return the number of sections
return 1
}
func tableView(_ tableView: UITableView, numberOfRowsInSection section: Int) -> Int {
// #warning Incomplete implementation, return the number of rows
return comments.count
}
func tableView(_ tableView: UITableView, cellForRowAt indexPath: IndexPath) -> UITableViewCell {
let cell = tableView.dequeueReusableCell(withIdentifier: reuseIdentifer, for: indexPath) as! FeedCell
imageFiles[indexPath.row].getDataInBackground { (data, error) in
if let imageData = data {
if let imageToDisplay = UIImage(data: imageData) {
cell.postImage.image = imageToDisplay
}
}
}
cell.descriptionLabel.text = comments[indexPath.row]
cell.userButton.setTitle("\(usernames[indexPath.row]) \(lastnames[indexPath.row])", for: UIControl.State.normal)
cell.userButton.addTarget(self, action: #selector(showProfile), for: .touchUpInside)
return cell
}
//skiped
}
非常感谢!
汤姆
答案 0 :(得分:1)
这里的问题是您的按钮可以在选择器上使用,并且对发件人或调用它的位置一无所知。
我将通过创建自定义表格视图单元格(例如FeedCell
)来实现此目的,该单元格允许您设置delegate
(例如FeedCellDelegate
)。将您的类设置为该单元的委托,并将当前的indexPath
传递到该单元中。然后,您可以在委托调用中返回indexPath
。
示例:请注意,为简单起见,已删除了代码,并且尚未测试此代码。这只是为了指导您正确的方向。
视图控制器
import UIKit
class HomeController: UIViewController {
// stripped additional information for example
func showProfile(_ username: String) {
let vc: AProfileViewController!
vc = AProfileViewController()
vc.username = username
vc.modalPresentationStyle = .fullScreen
present(vc, animated: true)
}
}
extension HomeController: UITableViewDelegate, UITableViewDataSource {
func tableView(_ tableView: UITableView, numberOfRowsInSection section: Int) -> Int {
return comments.count
}
func tableView(_ tableView: UITableView, cellForRowAt indexPath: IndexPath) -> UITableViewCell {
let cell = tableView.dequeueReusableCell(withIdentifier: reuseIdentifer, for: indexPath) as! FeedCell
cell.delegate = self
cell.descriptionLabel.text = comments[indexPath.row]
cell.userButton.setTitle("\(usernames[indexPath.row]) \(lastnames[indexPath.row])", for: UIControl.State.normal)
cell.setIndex(indexPath)
return cell
}
}
extension HomeController: FeedCellDelegate {
func didPressButton(_ indexPath: IndexPath) {
let userName = usernames[indexPath.row]
showProfile(username)
}
}
Feed单元格
import UIKit
protocol FeedCellDelegate {
didPressButton(_ indexPath: IndexPath)
}
class FeedCell: UICollectionViewCell {
var delegate: FeedCellDelegate?
var indexPath: IndexPath
@IBOutlet weak var userButton: UIButton
setIndex(_ indexPath: IndexPath) {
self.indexPath = indexPath
}
@IBAction userButtonPressed() {
if(delegate != nil) {
delegate?.didPressButton(indexPath)
}
}
}
答案 1 :(得分:0)
通常,您可以通过类型安全的方式获取任何响应者的父响应者:
extension UIResponder {
func firstParent<T: UIResponder>(ofType type: T.Type ) -> T? {
return next as? T ?? next.flatMap { $0.firstParent(ofType: type) }
}
}
所以:
@objc func showProfile(_ sender: UIButton) {
guard let cell = firstParent(ofType: UITableViewCell.self),
let indexPath = tableView.indexPath(for: cell) else {
return
}
let user = users[indexPath.row]
... do other stuff here ...
}