Question

<pre class="cake-debug">
Array
(
[0] => Array
    (
        [Qnote] => Array
            (
                [id] => 67
                [subject] => Call Closing
                [body] => Gave Information

                [user_id] => 39
            )

        [Step] => Array
            (
                [0] => Array
                    (
                        [id] => 2
                        [user_id] => 39
                        [qnote_id] => 67
                        [type] => a
                        [body] => This is a text
                    )

                [1] => Array
                    (
                        [id] => 3
                        [user_id] => 39
                        [qnote_id] => 67
                        [type] => a
                        [body] => This is userid 39

                    )



            )

    )

）

嗨，我正在尝试从此数组中提取数据

<?php foreach($data as $qnote): ?> 
<?php echo $qnote['Qnote']['id']; ?> // Works
<?php echo $qnote['Qnote']['body']; ?> //Works
<?php echo $qnote['Step']['body']; ?> // Doesnt Work ????
<?php endforeach; ?>

提取步骤数据的正确方法是什么。有人可以指出我正确的方向。

控制器代码：

function view($id = null) {         
$this->Qnote->id = $id;
$userID = $this->Authsome->get('id');       

$this->paginate = array(

'conditions' => array(
'Qnote.id LIKE' => $id), 
   );
$data = $this->paginate('Qnote');
$this->set('data', $data);
}

Answer 1

$qnote['Step']也是一个多维数组，所以你也需要循环遍历它：

<?php foreach ($data as $qnote) : ?>
    <p>Id: <?php echo $qnote['Qnote']['id']; ?></p>
    <p>Body: <?php echo $qnote['Qnote']['body']; ?></p>
    <p>
        Steps:
        <ul>
            <?php foreach ($qnote['Step'] as $step) : ?>
                <li><?php echo $step['body']; ?></li>
            <?php endforeach; ?>
        </ul>
    </p>
<?php endforeach; ?>

Answer 2

记下：

<?php echo $qnote['Step']['body']; ?> // Doesnt Work ????

其中$qnote['Step']是：

[Step] => Array
(
    [0] => Array
    (
        [id] => 2
        [user_id] => 39
        [qnote_id] => 67
        [type] => a
        [body] => This is a text
     )
    [1] => Array
    (
        [id] => 3
        [user_id] => 39
        [qnote_id] => 67
        [type] => a
        [body] => This is userid 39
    )
)

没有$qnote['Step']['body']。但是有$qnote['Step'][1]['body']。

如果您想访问['body']中的所有$qnote['Step']，请使用foreach：

foreach($qnote['Step'] as $step)
{
    echo $step['body'];
}

编辑：第二个想法，还要注意'Step'不是'Qnote'的成员（可能不是$ qnote。）你可能想先解决这个问题。

从数组中提取信息

2 个答案: