Question

基本上，我想做的是创建一个编组器，该编组器可以接受我给它的任何类对象，例如汽车对象或人对象，并且必须返回XML字符串。

这是到目前为止我得到的：

 public <T> String CreateXML(T objToSerialize)
    {
        String xml = "";
        try 
        {           

        JAXBContext context = JAXBContext.newInstance(objToSerialize.getClass());
        Marshaller marshaler = context.createMarshaller(); 
        StringWriter writer = new StringWriter();
        marshaler.marshal(objToSerialize.getClass(),writer);
        xml = writer.toString();
            System.out.println(xml);
            return xml;
        } catch (Exception e) {
            System.out.println(e.getMessage());
        }
        return xml;
    }

它给我以下错误：

警告：发生了非法的反射访问操作

Answer 1

在您的代码中，封送objectToSerialize的类而不是对象本身。您可以更改此行

 marshaler.marshal(objToSerialize.getClass(),writer);
 //to
 marshaler.marshal(objToSerialize,writer);

或尝试以下代码：

public static <T> String marshall(T data) {
    try {
        JAXBContext jaxbContext = JAXBContext.newInstance(data.getClass());
        Marshaller jaxbMarshaller = jaxbContext.createMarshaller();
        StringWriter stringWriter=new StringWriter();
        jaxbMarshaller.setProperty(Marshaller.JAXB_FORMATTED_OUTPUT,true);
        jaxbMarshaller.marshal(data, stringWriter);
        return stringWriter.toString();
    } catch (JAXBException e) {
        e.printStackTrace();
    }
    return null;
}

Answer 2

对于通用转换，试试这个：

StringWriter sw = new StringWriter();
JAXBContext.newInstance(((JAXBElement) argument).getDeclaredType()).createMarshaller().marshal(argument, sw);
sb.append(sw.toString());

如何创建采用通用对象的JAXB Marshaller

2 个答案: