while($row = mysqli_fetch_row($result)){
$time=$row[0];
$name=$row[1];
$pat_id=$row[2];
?>
<div class="col-12 shadow m-2">
<ul class=" list-group-flush">
<li class="list-group-item">
<div class="d-flex m-0 p-0 justify-content-around text-justify">
<div>
<?php echo $time; ?>
</div>
<div id="Name">
<?php echo $pat_id.$name; ?>
</div>
<div>
</a> Cancel </a><button type="button" class="btn btn-danger btn-circle btn-sm" ><i class="fa fa-minus" style="font-size:14px;"></i> </button>
</div>
<div>
<form method="get" action="sample.php">
<input type="hidden" name="patient" value=<?php $name ?>>
</a> ADD </a><button type="submit" href="sample.html" class="btn btn-primary btn-circle btn-sm" id="clickbtn"><i class="fa fa-plus" style="font-size:14px;"></i> </button>
</div>
</form>
</div>
</li>
</ul>
</div>
<?php
}
?>
</div>
在这里,我想将变量传递到添加按钮中的下一页,并删除在取消按钮中传递的变量,但这仅适用于最后一个按钮
答案 0 :(得分:0)
您可以只使用查询参数来构成一个URL,而不是使用get form
<a href="sample.php?patient=<?=$name?>">Add</a>