在控制器中使用自定义中间件

Question

我创建了中间件：php artisan make:middleware CheckUserStatus

在这个中间件中，我有：

namespace App\Http\Middleware;

use Closure;

class CheckUserStatus
{
    /**
     * Handle an incoming request.
     *
     * @param  \Illuminate\Http\Request  $request
     * @param  \Closure  $next
     * @return mixed
     */
    public function handle($request, Closure $next)
    {
        if(Auth()->check() AND Auth()->user()->status === 0) { // user is logged in but it is blocked
            auth()->logout();
            return redirect('/');
        }

        return $next($request);
    }
}

然后，我有一个控制器：

namespace App\Http\Controllers;

use Illuminate\Http\Request;

use App\Http\Middleware\CheckUserStatus;


class productsController extends Controller
{
    public function __construct () {
        $this->middleware('auth');
        $this->middleware('CheckUserStatus');
    }
}

这给出了ReflectionException - Class CheckUserStatus does not exist

我做错了什么？

Answer 1

如果要通过字符串键引用中间件，则需要注册。选中out the docs here.

或者，您可以使用完全限定的类名：尝试使用// Force Gradle to load the JUnit Platform Launcher from the module-path testRuntimeOnly("org.junit.platform", "junit-platform-launcher") { version { strictly("[1.5, 2.0]") prefer("1.5.2") } because("my reason here.") } 而不是CheckUserStatus::class。

Answer 2

您需要使用完全限定的类名：

要么：

namespace App\Http\Controllers;

use Illuminate\Http\Request;

class productsController extends Controller
{
    public function __construct () {
        $this->middleware('auth');
        $this->middleware('\App\Http\Middleware\CheckUserStatus');
    }
}

或

namespace App\Http\Controllers;

use Illuminate\Http\Request;

use App\Http\Middleware\CheckUserStatus;

class productsController extends Controller
{
    public function __construct () {
        $this->middleware('auth');
        $this->middleware(CheckUserStatus::class); //No quotes
    }
}

Answer 3

您需要在kernel.php中添加中间件

protected $routeMiddleware = [

       'your_desire_name'=>\App\Http\Middleware\CheckUserStatus::class,
    ];