Question

有人可以告诉我为什么应用程序会抛出这个吗？

W/System.err: javax.mail.AuthenticationFailedException
        at javax.mail.Service.connect(Service.java:319)
        at javax.mail.Service.connect(Service.java:169)
        at javax.mail.Service.connect(Service.java:118)
        at javax.mail.Transport.send0(Transport.java:188)
W/System.err:     at javax.mail.Transport.send(Transport.java:118)
        at com.example.**.Utils.SendMail.doInBackground(SendMail.java:71)
        at com.example.**.Utils.SendMail.doInBackground(SendMail.java:19)
        at android.os.AsyncTask$3.call(AsyncTask.java:378)
        at java.util.concurrent.FutureTask.run(FutureTask.java:266)
        at android.os.AsyncTask$SerialExecutor$1.run(AsyncTask.java:289)
        at java.util.concurrent.ThreadPoolExecutor.runWorker(ThreadPoolExecutor.java:1167)
        at java.util.concurrent.ThreadPoolExecutor$Worker.run(ThreadPoolExecutor.java:641)
        at java.lang.Thread.run(Thread.java:919)

我正在尝试使用javamail api发送邮件。

我想提一下，我检查了邮件帐户，但安全性较差的应用程序。

这是SendMail类

package com.example.****.Utils;


import android.content.Context;
import android.os.AsyncTask;
import android.widget.Toast;

import java.util.Properties;

import javax.mail.Message;
import javax.mail.MessagingException;
import javax.mail.PasswordAuthentication;
import javax.mail.Session;
import javax.mail.Transport;
import javax.mail.internet.InternetAddress;
import javax.mail.internet.MimeMessage;


public class SendMail extends AsyncTask<Void, Void, Void> {

  private Context context;
  private Session session;


  private String email;
  private String subject;
  private String message;

  public SendMail(Context context, String email, String subject, String message)
  {
      this.context = context;
      this.email = email;
      this.subject = subject;
      this.message = message;
  }

  @Override
    protected void onPreExecute() {
      super.onPreExecute();
      Toast.makeText(context, "Sending mail...", Toast.LENGTH_SHORT).show();
  }

  @Override
    protected void onPostExecute(Void aVoid)
  {
      super.onPostExecute(aVoid);
      Toast.makeText(context, "Message Sent", Toast.LENGTH_SHORT).show();
  }

  @Override
    protected Void doInBackground(Void... params) {
      Properties props = new Properties();
      props.put("mail.smtp.host", "smtp.gmail.com");
      props.put("mail.smtp.socketFactory.port", "465");
      props.put("mail.smtp.socketFactory.class", "javax.net.ssl.SSLSocketFactory");
      props.put("mail.smtp.auth", "true");
      props.put("mail.smtp.port", "465");

      session = Session.getDefaultInstance(props, new javax.mail.Authenticator() {
          protected  PasswordAuthentication getPasswordAuthentication() {
              return new PasswordAuthentication(Config.EMAIL, Config.PASSWORD);
          }
      });
      try {
          MimeMessage mm = new MimeMessage(session);
          mm.setFrom(new InternetAddress(Config.EMAIL));
          mm.addRecipient(Message.RecipientType.TO, new InternetAddress(email));
          mm.setSubject(subject);
          mm.setText(message);

          Transport.send(mm);
      }
      catch (MessagingException e) {
          e.printStackTrace();
      }
      return null;
  }
}

这里我正在使用它

  String email = "******";
        String subject = "Activation";
        String message = "This User requires activation: " + "<a href='http://localhost:80/approve/" +mAuth.getCurrentUser().getEmail() +"> Click here </a>";

        SendMail sm = new SendMail(this, email, subject,message);
        sm.execute();

我提供了正确的密码，我检查了自己的Google帐户，该密码应该可以正常工作你能帮我吗？

提前谢谢！

Answer 1

您的实现中缺少一个属性。

在您的props.put("mail.smtp.ssl.trust", "smtp.gmail.com");方法中使用doInBackground()可以解决此问题。

说明： Gmail requires SSL

来自java mail documentation：下面的代码片段显示了一种在应用程序中合并所需配置的简单方法：

String host = "smtp.gmail.com";
String username = "user";
String password = "passwd";
Properties props = new Properties();
props.setProperty("mail.smtp.host", host);
props.setProperty("mail.smtp.ssl.enable", "true");
// set any other needed mail.smtp.* properties here
Session session = Session.getInstance(props);
MimeMessage msg = new MimeMessage(session);
// set the message content here
Transport.send(msg, username, password);

为什么我收到javax.mail.AuthenticationFailedException？

1 个答案: