Question

我有以下代码，用于根据发送日期和电子邮件主题条件下载电子邮件附件：

hive.exec.dynamic.partition = true; 
hive.exec.dynamic.partition.mode = nonstrict;

例如，是否可以指定仅下载.csv附件的条件？

此外，此代码以前曾在公用文件夹上使用-现在这些文件夹已更新为共享文件夹。自更新以来，我不得不将“最大”值从500增加到2500，以便查找指定的电子邮件。有什么办法可以加快速度吗？

谢谢

Answer 1

下面是一种指定所需文件类型的方法。

请在“ attachments_of_interest”列表中输入文件结尾。

from datetime import date, timedelta
import os
import win32com.client


path = os.path.expanduser("C:\\Users\\xxxx\\Documents\\Projects\\VBA Projects\\VLOOKUP Automation\\Vlookup File Location")
today = date.today()

outlook = win32com.client.Dispatch("Outlook.Application").GetNamespace("MAPI")
inbox = outlook.Folders("xxx").Folders.Item("Inbox")
messages = inbox.Items
subject = "xxx"

dateHigh = date.today() - timedelta(days=1)
dateLow = date.today() - timedelta(days=-1)

max_n = 2500
attachments_of_interest = ['.csv']

for count, message in enumerate(messages):
    if count > max_n:
        break
    if subject in message.subject and message.senton.date() > dateLow and message.senton.date() < dateHigh:
        attachments = message.Attachments
        num_attach = len([x for x in attachments])
        for x in range(1, num_attach+1):
            attachment = attachments.Item(x)
            attachment_fname = str(attachment)
            file_ending = attachment_fname.split('.')[-1]
            if not attachments_of_interest or file_ending in attachments_of_interest:
                attachment.SaveASFile(path + '\\' + attachment_fname)

关于加速，您可以使用一个池：

from multiprocessing.pool import ThreadPool as Pool
from datetime import date, timedelta
import os
import win32com.client


path = os.path.expanduser("C:\\Users\\xxxx\\Documents\\Projects\\VBA Projects\\VLOOKUP Automation\\Vlookup File Location")
today = date.today()

outlook = win32com.client.Dispatch("Outlook.Application").GetNamespace("MAPI")
inbox = outlook.Folders("xxx").Folders.Item("Inbox")
messages = inbox.Items
subject = "xxx"

max_n = 2500
attachments_of_interest = ['.csv']
pool_size = 5

# define worker function before a Pool is instantiated
def worker(message):
    dateHigh = date.today() - timedelta(days=1)
    dateLow = date.today() - timedelta(days=-1)
    if subject in message.subject and message.senton.date() > dateLow and message.senton.date() < dateHigh:
        attachments = message.Attachments
        num_attach = len([x for x in attachments])
        for x in range(1, num_attach+1):
            attachment = attachments.Item(x)
            attachment_fname = str(attachment)
            file_ending = attachment_fname.split('.')[-1]
            if not attachments_of_interest or file_ending in attachments_of_interest:
                attachment.SaveASFile(path + '\\' + attachment_fname)

pool = Pool(pool_size)

for count, message in enumerate(messages):
    if count > max_n:
        break
    pool.apply_async(worker, (message,))

pool.close()
pool.join()

Answer 2

我认为这是仅下载csv的要求的一部分。此Outlook组件具有一些可以利用的方法。而不是消息= inbox.Items 尝试消息= inbox.Items.GetFirst（）并获得第一条消息，然后使用

消息= inbox.Items.oItems.GetNext（）因此，这样一来，您在内存中始终只有一条消息，并且可以使循环时间更长。

确保您具有Outlook Microsoft Outlook 16.0对象库或高于10的对象库，以便此方法存在。 GetFirst（）我使用的C＃代码

Outlook.MailItem oMsg = (Outlook.MailItem)oItems.GetFirst();

                    //Output some common properties.
                    Console.WriteLine(oMsg.Subject);
                    Console.WriteLine(oMsg.SenderName);
                    Console.WriteLine(oMsg.ReceivedTime);
                    Console.WriteLine(oMsg.Body);

                    //Check for attachments.
                    int AttachCnt = oMsg.Attachments.Count;
                    Console.WriteLine("Attachments: " + AttachCnt.ToString());
                Outlook.MailItem oMsg1 = (Outlook.MailItem)oItems.GetNext();

从共享文件夹下载电子邮件附件-Python

2 个答案: