Question

我的json文件包含以下数据：文件名：“ masterData.json”

{
  "Devices":[
    {"DeviceID":"WS1272765443SA",
      "DeviceModel":"model",
      "SerialNumber":"121",
      "Status":"available"
    },
    {
      "DeviceID":"WS1215",
      "DeviceModel":"eCP Tablet",
      "SerialNumber":"122",
      "Status":"available"

    }
  ],
  "Organization":[
    {
      "OrgName":"abc",
      "UserName":"hello",
      "OrgId":"abc",
      "CommunityURL":"",
      "ApiVersionValue":"1.0",
      "OrgCode":"Orgcode11",
      "OrgType":"en",
      "NameSpace":"h",
    }
  ],
  "DeviceModels":[
    {
      "BrandName":"",
      "ModelNameValue":"",
      "Config":""
    },
    {
      "BrandName":"",
      "ModelNameValue":"",
      "Config":""
    }
  ]
}

我需要为每个设备添加deviceNumber和值，还需要将Status从可用更新为活动，这样我的“ masterData.json”看起来像

{
  "Devices":[
    {
      "DeviceID":"WS1272765443SA",
      "DeviceModel":"model",
      "SerialNumber":"121",
      "Status":**"active"**,
      **"deviceNumber":"123456D"**

    },
    {
      "DeviceID":"WS1215",
      "DeviceModel":"eCP Tablet",
      "SerialNumber":"122",
      "Status":**active**,
      **"deviceNumber":"1234f"**

    }
  ],
  "Organization":[
    {
      "OrgName":"abc",
      "UserName":"hello",
      "OrgId":"abc",
      "CommunityURL":"",
      "ApiVersionValue":"1.0",
      "OrgCode":"Orgcode11",
      "OrgType":"en",
      "NameSpace":"h",
    }
  ],
  "DeviceModels":[
    {
      "BrandName":"",
      "ModelNameValue":"",
      "Config":""
    },
    {
      "BrandName":"",
      "ModelNameValue":"",
      "Config":""
     }
  ]
}

请帮助我使用Java代码。

我尝试使用下面的Java代码，但无法实现。

FileReader reader = new FileReader(utility.getValue("MasterJsonPath"));
JsonObject jsonObj = (JsonObject) parser.parse(reader);
JsonArray deviceListFromJSON = (JsonArray) jsonObj.get("Devices");

for (int i = 0; i < deviceListFromJSON.size(); i++) {

  JsonObject devices = (JsonObject) deviceListFromJSON.get(i);
   ObjectMapper mapper = new ObjectMapper();
   devices.addProperty("device number", "device value");
   deviceListFromJSON.add(devices);
  mapper.writer().writeValue(new File(utility.getValue("MasterJsonPath")),deviceListFromJSON);
}
}

Answer 1

首先，您的fisrt json代码格式错误（多余的逗号，缺少{“ Devices”，..）。

我试图纠正它：

{"Devices": [
    {"DeviceID":"WS1272765443SA",
     "DeviceModel":"model",
     "SerialNumber":"121",
     "Status":"available"
    },
    {"DeviceID":"WS1215",
     "DeviceModel":"eCP Tablet",
     "SerialNumber":"122",
     "Status":"available"
 }],
"Organization": [
   {"OrgName":"abc",
    "UserName":"hello",
    "OrgId":"abc",
    "CommunityURL":"",
    "ApiVersionValue":"1.0",
    "OrgCode":"Orgcode11",
    "OrgType":"en",
    "NameSpace":"h"
}],
"DeviceModels":[
   {"BrandName":"",
    "ModelNameValue":"",
    "Config":""
   },
   {"BrandName":"",
    "ModelNameValue":"",
    "Config":""
}]}

对于Java代码，请尝试在for循环的末尾保存文件。并编写整个jsonobject“ jsonObj ”，而不仅是 deviceListFromJSON 。另外，请在“ deviceNumber ”和“ 状态”上都使用 addProperty 。希望它会有所帮助：）

    FileReader reader = new FileReader("file.json");
    JsonParser parser = new JsonParser() ;
    JsonObject jsonObj = (JsonObject) parser.parse(reader);
    JsonArray deviceListFromJSON = (JsonArray) jsonObj.get("Devices");
    reader.close();
    for (int i = 0; i < deviceListFromJSON.size(); i++) {
        JsonObject devices = (JsonObject) deviceListFromJSON.get(i);
        devices.addProperty("deviceNumber", "1234f");
        devices.addProperty("Status", "active");
    }   
    BufferedWriter writer = new BufferedWriter(new FileWriter("file.json"));
    writer.write(jsonObj.toString());
    writer.close();

在Java

1 个答案: