Question

我想做的是在我想从小处开始的“ mktrateestimate”中显示“ currgroupinputrate”和“ mktratedelta”的加法，因此我尝试在“ mktratedelta”输入字段中输入内容，然后应显示此输入以mktrateestimate表示，但未在mktratedelta中显示输入。如何解决此问题，正确的方法是什么？

const [marketEstimateDataBCAssets, setmarketEstimateData] = useState([
    {
      name: "Lombard",
      prevgroupinputrate: 0.01,
      currgroupinputrate: 0.02,
      mktratedelta: 0.03,
      mktrateestimate: 0.04
    },
    {
      name: "Other Secured",
      prevgroupinputrate: 0.01,
      currgroupinputrate: 0.02,
      mktratedelta: 0.033,
      mktrateestimate: 0.04
    },
    {
      name: "Unsecured",
      prevgroupinputrate: 0.01,
      currgroupinputrate: 0.02,
      mktratedelta: 0.0333,
      mktrateestimate: 0.04
    }
  ]);


  return (
      {marketEstimateDataBCAssets.map((item, key) => {
        return (
          <Segment>
            <div> {item.name}</div>
            <div> {item.prevgroupinputrate}</div>
            <div> {item.currgroupinputrate}</div>
            <input
              value={item.mktratedelta}
              onChange={e => {
                const newArr = marketEstimateDataBCAssets.map(el => {
                  if (el.name === item.name) {
                    return { ...el, mktratedelta: parseFloat(e.target.value) };
                  }
                  return el;
                });
                console.log(newArr);

                return setmarketEstimateData([...newArr]);
              }}
            />
            <div> {marketEstimateDataBCAssets[key].mktrateestimate}</div>
          </Segment>
        );
      })} ```

Answer 1

您应该尝试类似code的操作。这只是您可以从那里继续进行的开始。您应该找到一种方法来管理受控的select s.* from (select s.*, row_number() over (partition by user_id order by date_submitted desc) as seqnum, lag(submission) over (partition by user_id order by date_submitted) as prev_submission from submissions s ) s where prev_submission is not null and submission is null and seqnum = 1;。有关更多信息，请阅读React中的Uncontrolled Components和Controlled Components。在JavaScript中查看parseFloat。

input

如何使用映射React从useState添加2个键？

1 个答案: