Question

我有一个检查当前时间是否在工作时间内的功能-目前，我仅使用布尔函数检查工作时间，夏令时和周末。

如何设置假期日期列表，并具有功能来检查今天的当前日期是否是假期，如果不是，则返回true，否则返回false。

最好的方法是创建一个日期数组，这样吗？

 var holidays = { // keys are formatted as month,day
 "0,1": "Martin Luther King, Jr. Day",      
 "1,1": "President's Day",                 
 "2,0": "Daylight Savings Time Begins",     
 "3,3": "Administrative Professionals Day",
 "4,0": "Mother's Day",                     
 "4,1": "Memorial Day",                     
 "5,0": "Father's Day",                     
 "6,0": "Parents Day",                     
 "8,1": "Labor Day",                                                            
 "8,0": "Gold Star Mothers Day",           
 "9,1": "Columbus Day",                     
 "10,0": "Daylight Savings Time Ends",      
 "10,4": "Thanksgiving Day"                 
 }; 


 //or like this?

 var holidays = ["Martin Luther King, Jr. Day": {

 "day":"1",
 "month":"0"
 },

 "President's Day": {

 "day":"1",
 "month":"1"
 }];

然后检查是否 date.getMonth（） date.getDate（）

等于列表中的一项，然后返回true，否则返回false

这样的作品行吗？

 function checkHoliday(){

 month = date.getMonth()
 date = date.getDate()


 for (var i=0; i < holidays.length ;i++){

 if(holidays[i].day == date && holidays[i].month == month) {

 return true

 } else return false;

 }

Answer 1

您不需要循环，因为您只需构建密钥并检查它是否存在
您可以直接返回要检查的值，而不用使用if / else返回true或false。

示例

function checkHoliday(){
    var month = date.getMonth();
    var date = date.getDate();
    return holidays.hasOwnProperty(month + ',' + date);
}

Answer 2

我会做这样的事情：

const holidays = [
  {name: 'Martin Luther King, Jr. Day', day: 20, month: 1},
  {name: 'Presidents Day', day: 17, month: 2}
];

function checkHoliday(){
  const today = new Date(); // get date of today
  for(var i = 0; i < holidays.length; i++){
    let isHoliday = holidays[i].day === today.getDate() && holidays[i].month === today.getMonth() + 1; // check if today is a holiday
    if(isHoliday) return true; // return true if today is a holiday
    // you could also return which holiday it is using: if(isHoliday) return holidays[i].name;
  }
  return false; // else return false
}

console.log(checkHoliday());

但是，我认为对此的怀念比我的想法更好。只有一件事：

如果有，您可以返回假日名称而不是true 当天没有假期，它将返回undefined。

const holidays = {
  "0,1": "Martin Luther King, Jr. Day",
  "1,1": "President's Day",
  "2,0": "Daylight Savings Time Begins",
  "3,3": "Administrative Professionals Day",
  "4,0": "Mother's Day",
  "4,1": "Memorial Day",
  "5,0": "Father's Day",
  "6,0": "Parents Day",
  "8,1": "Labor Day",
  "8,0": "Gold Star Mothers Day",
  "9,1": "Columbus Day",
  "10,0": "Daylight Savings Time Ends",
  "10,4": "Thanksgiving Day"
};

let date = new Date();

function checkHoliday() {
  const month = date.getMonth();
  const day = date.getDate();
  return holidays[month + ',' + day];
}

// As you can see, this could also be used like a boolean:

if(checkHoliday()) console.log('true because the function returns:', checkHoliday());
else console.log('false because the function returns:', checkHoliday());

// The following is only to fake a holiday:

document.getElementById('makeHoliday').onclick = () => {
  date = new Date(2019, 0, 1);
  if(checkHoliday()) console.log('true because the function returns:', checkHoliday());
  else console.log('false because the function returns:', checkHoliday());
}

<button id="makeHoliday">Klick here to fake a holiday</button>

如果当前日期是节假日，则返回布尔型JavaScript函数

2 个答案: