Question

如何用--strategy recursive -X ours分隔行中的单词：

Answer 1

这是您要寻找的吗？

line = "10103;Baldwin, C;SFEN 10115;Wyatt, X;SFEN 10172;Forbes, I;SFEN 10175;Erickson, D;SFEN 10183;Chapman, O;SFEN 11399;Cordova, I;SYEN 11461;Wright, U;SYEN 11658;Kelly, P;SYEN 11714;Morton, A;SYEN 11788;Fuller, E;SYEN"
line.split(";")

输出

['10103',
 'Baldwin, C',
 'SFEN 10115',
 'Wyatt, X',
 'SFEN 10172',
 'Forbes, I',
 'SFEN 10175',
 'Erickson, D',
 'SFEN 10183',
 'Chapman, O',
 'SFEN 11399',
 'Cordova, I',
 'SYEN 11461',
 'Wright, U',
 'SYEN 11658',
 'Kelly, P',
 'SYEN 11714',
 'Morton, A',
 'SYEN 11788',
 'Fuller, E',
 'SYEN']

Answer 2

一种选择：

"10103;Baldwin, C;SFEN".split(";")

但是，我认为您想将所有内容（包括逗号）分开，所以我将替换“;”首先是逗号，然后按逗号进行分割。

Answer 3

我建议为此使用csv，尽管如果您输入的内容实际上是一个字符串，那么您将需要io.StringIO或仅用换行符分隔：

import csv
from io import StringIO

s = """10103;Baldwin, C;SFEN
10115;Wyatt, X;SFEN
10172;Forbes, I;SFEN
10175;Erickson, D;SFEN
10183;Chapman, O;SFEN
11399;Cordova, I;SYEN
11461;Wright, U;SYEN
11658;Kelly, P;SYEN
11714;Morton, A;SYEN
11788;Fuller, E;SYEN"""

reader = csv.reader(s.split('\n'), delimiter=';')
#or
reader = csv.reader(StringIO(s), delimiter=';')
for line in reader:
    print(line)

输出：

['10103', 'Baldwin, C', 'SFEN']
['10115', 'Wyatt, X', 'SFEN']
['10172', 'Forbes, I', 'SFEN']
['10175', 'Erickson, D', 'SFEN']
['10183', 'Chapman, O', 'SFEN']
['11399', 'Cordova, I', 'SYEN']
['11461', 'Wright, U', 'SYEN']
['11658', 'Kelly, P', 'SYEN']
['11714', 'Morton, A', 'SYEN']
['11788', 'Fuller, E', 'SYEN']

如何在以“;”分隔的文件行中分割单词

3 个答案: