Question

是否可以用System.Text.Json?合并这样的两个json对象

对象1

{
   id: 1
   william: "shakespeare"
}

对象2

{
   william: "dafoe"
   foo: "bar"
}

结果对象

{
    id: 1
    william: "dafoe"
    foo: "bar"
}

我可以使用newtonsoft.json这样实现它

var obj1 = JObject.Parse(obj1String);
var obj2 = JObject.Parse(obj2String);

obj1.Merge(obj2);
result = settings.ToString();

但是System.Text.Json有办法吗？

Answer 1

已经存在为System.Text.Json请求此功能的问题：https://github.com/dotnet/corefx/issues/42466

同时，您可以基于Merge编写自己的Utf8JsonWriter方法作为解决方法（因为现有的JsonDocument，JsonElement API是只读的）

如果您的JSON对象仅包含非null的简单/原始值，并且属性显示的顺序并不特别在意，则以下相对简单的代码示例应该对您有用：

public static string SimpleObjectMerge(string originalJson, string newContent)
{
    var outputBuffer = new ArrayBufferWriter<byte>();

    using (JsonDocument jDoc1 = JsonDocument.Parse(originalJson))
    using (JsonDocument jDoc2 = JsonDocument.Parse(newContent))
    using (var jsonWriter = new Utf8JsonWriter(outputBuffer, new JsonWriterOptions { Indented = true }))
    {
        JsonElement root1 = jDoc1.RootElement;
        JsonElement root2 = jDoc2.RootElement;

        // Assuming both JSON strings are single JSON objects (i.e. {...})
        Debug.Assert(root1.ValueKind == JsonValueKind.Object);
        Debug.Assert(root2.ValueKind == JsonValueKind.Object);

        jsonWriter.WriteStartObject();

        // Write all the properties of the first document that don't conflict with the second
        foreach (JsonProperty property in root1.EnumerateObject())
        {
            if (!root2.TryGetProperty(property.Name, out _))
            {
                property.WriteTo(jsonWriter);
            }
        }

        // Write all the properties of the second document (including those that are duplicates which were skipped earlier)
        // The property values of the second document completely override the values of the first
        foreach (JsonProperty property in root2.EnumerateObject())
        {
            property.WriteTo(jsonWriter);
        }

        jsonWriter.WriteEndObject();
    }

    return Encoding.UTF8.GetString(outputBuffer.WrittenSpan);
}

Newtonsoft.Json在合并时null具有不同的null处理方式，其中null不会覆盖non-null属性的值（当存在重复项时）。我不确定您是否要这样做。如果需要，您将需要修改上述方法来处理public static string SimpleObjectMergeWithNullHandling(string originalJson, string newContent) { var outputBuffer = new ArrayBufferWriter<byte>(); using (JsonDocument jDoc1 = JsonDocument.Parse(originalJson)) using (JsonDocument jDoc2 = JsonDocument.Parse(newContent)) using (var jsonWriter = new Utf8JsonWriter(outputBuffer, new JsonWriterOptions { Indented = true })) { JsonElement root1 = jDoc1.RootElement; JsonElement root2 = jDoc2.RootElement; // Assuming both JSON strings are single JSON objects (i.e. {...}) Debug.Assert(root1.ValueKind == JsonValueKind.Object); Debug.Assert(root2.ValueKind == JsonValueKind.Object); jsonWriter.WriteStartObject(); // Write all the properties of the first document that don't conflict with the second // Or if the second is overriding it with null, favor the property in the first. foreach (JsonProperty property in root1.EnumerateObject()) { if (!root2.TryGetProperty(property.Name, out JsonElement newValue) || newValue.ValueKind == JsonValueKind.Null) { property.WriteTo(jsonWriter); } } // Write all the properties of the second document (including those that are duplicates which were skipped earlier) // The property values of the second document completely override the values of the first, unless they are null in the second. foreach (JsonProperty property in root2.EnumerateObject()) { // Don't write null values, unless they are unique to the second document if (property.Value.ValueKind != JsonValueKind.Null || !root1.TryGetProperty(property.Name, out _)) { property.WriteTo(jsonWriter); } } jsonWriter.WriteEndObject(); } return Encoding.UTF8.GetString(outputBuffer.WrittenSpan); }情况。修改如下：

public static string Merge(string originalJson, string newContent)
{
    var outputBuffer = new ArrayBufferWriter<byte>();

    using (JsonDocument jDoc1 = JsonDocument.Parse(originalJson))
    using (JsonDocument jDoc2 = JsonDocument.Parse(newContent))
    using (var jsonWriter = new Utf8JsonWriter(outputBuffer, new JsonWriterOptions { Indented = true }))
    {
        JsonElement root1 = jDoc1.RootElement;
        JsonElement root2 = jDoc2.RootElement;

        if (root1.ValueKind != JsonValueKind.Array && root1.ValueKind != JsonValueKind.Object)
        {
            throw new InvalidOperationException($"The original JSON document to merge new content into must be a container type. Instead it is {root1.ValueKind}.");
        }

        if (root1.ValueKind != root2.ValueKind)
        {
            return originalJson;
        }

        if (root1.ValueKind == JsonValueKind.Array)
        {
            MergeArrays(jsonWriter, root1, root2);
        }
        else
        {
            MergeObjects(jsonWriter, root1, root2);
        }
    }

    return Encoding.UTF8.GetString(outputBuffer.WrittenSpan);
}

private static void MergeObjects(Utf8JsonWriter jsonWriter, JsonElement root1, JsonElement root2)
{
    Debug.Assert(root1.ValueKind == JsonValueKind.Object);
    Debug.Assert(root2.ValueKind == JsonValueKind.Object);

    jsonWriter.WriteStartObject();

    // Write all the properties of the first document.
    // If a property exists in both documents, either:
    // * Merge them, if the value kinds match (e.g. both are objects or arrays),
    // * Completely override the value of the first with the one from the second, if the value kind mismatches (e.g. one is object, while the other is an array or string),
    // * Or favor the value of the first (regardless of what it may be), if the second one is null (i.e. don't override the first).
    foreach (JsonProperty property in root1.EnumerateObject())
    {
        string propertyName = property.Name;

        JsonValueKind newValueKind;

        if (root2.TryGetProperty(propertyName, out JsonElement newValue) && (newValueKind = newValue.ValueKind) != JsonValueKind.Null)
        {
            jsonWriter.WritePropertyName(propertyName);

            JsonElement originalValue = property.Value;
            JsonValueKind originalValueKind = originalValue.ValueKind;

            if (newValueKind == JsonValueKind.Object && originalValueKind == JsonValueKind.Object)
            {
                MergeObjects(jsonWriter, originalValue, newValue); // Recursive call
            }
            else if (newValueKind == JsonValueKind.Array && originalValueKind == JsonValueKind.Array)
            {
                MergeArrays(jsonWriter, originalValue, newValue);
            }
            else
            {
                newValue.WriteTo(jsonWriter);
            }
        }
        else
        {
            property.WriteTo(jsonWriter);
        }
    }

    // Write all the properties of the second document that are unique to it.
    foreach (JsonProperty property in root2.EnumerateObject())
    {
        if (!root1.TryGetProperty(property.Name, out _))
        {
            property.WriteTo(jsonWriter);
        }
    }

    jsonWriter.WriteEndObject();
}

private static void MergeArrays(Utf8JsonWriter jsonWriter, JsonElement root1, JsonElement root2)
{
    Debug.Assert(root1.ValueKind == JsonValueKind.Array);
    Debug.Assert(root2.ValueKind == JsonValueKind.Array);

    jsonWriter.WriteStartArray();

    // Write all the elements from both JSON arrays
    foreach (JsonElement element in root1.EnumerateArray())
    {
        element.WriteTo(jsonWriter);
    }
    foreach (JsonElement element in root2.EnumerateArray())
    {
        element.WriteTo(jsonWriter);
    }

    jsonWriter.WriteEndArray();
}

如果您的JSON对象可能包含嵌套的JSON值（包括其他对象和数组），那么您也想扩展逻辑来处理它。这样的事情应该起作用：

Merge

注意：如果性能对于您的方案至关重要，则此方法（即使带有缩进形式）在运行时和分配方面均优于Newtonsoft.Json的outputBuffer方法。也就是说，可以根据需要使实现更快一些（例如，不要缩进，缓存BenchmarkDotNet=v0.12.0, OS=Windows 10.0.19041 Intel Core i7-6700 CPU 3.40GHz (Skylake), 1 CPU, 8 logical and 4 physical cores .NET Core SDK=5.0.100-alpha1-015914 [Host] : .NET Core 5.0.0 (CoreCLR 5.0.19.56303, CoreFX 5.0.19.56306), X64 RyuJIT Job-LACFYV : .NET Core 5.0.0 (CoreCLR 5.0.19.56303, CoreFX 5.0.19.56306), X64 RyuJIT PowerPlanMode=00000000-0000-0000-0000-000000000000，不接受/返回字符串等）。

|          Method |     Mean |    Error |   StdDev |   Median |      Min |      Max | Ratio |  Gen 0 |  Gen 1 | Gen 2 | Allocated |
|---------------- |---------:|---------:|---------:|---------:|---------:|---------:|------:|-------:|-------:|------:|----------:|
| MergeNewtonsoft | 29.01 us | 0.570 us | 0.656 us | 28.84 us | 28.13 us | 30.19 us |  1.00 | 7.0801 | 0.0610 |     - |  28.98 KB |
|       Merge_New | 16.41 us | 0.293 us | 0.274 us | 16.41 us | 16.02 us | 17.00 us |  0.57 | 1.7090 |      - |     - |   6.99 KB |

let maxDuration:Float64 = 60
let videoDuration = asset!.duration
let videoDurationSeconds = CMTimeGetSeconds(videoDuration)

   if videoDurationSeconds > maxDuration {
       if UIVideoEditorController.canEditVideoAtPath(asset!.URL.path!) {
              let videoEditor = UIVideoEditorController()
              self.videoEditor.videoPath = asset!.URL.path!
              self.videoEditor.videoMaximumDuration = 60.0
              self.presentViewController(self.videoEditor, animated: true, completion: nil)

             }

         }


// MARK: - UIVideoEditorControllerDelegate

func videoEditorController(editor: UIVideoEditorController, didSaveEditedVideoToPath editedVideoPath: String) { 

                 self.videoEditor.dismissViewControllerAnimated(true, completion: nil)
                            //Do whatever you wish with the trimmed video here
                        }

Answer 2

从.Net Core 3.0开始，System.Text.Json尚未实现JSON对象的合并：

JsonDocument上没有Merge或Populate方法。
JsonSerializer上没有Merge或Populate方法。

通常，JsonDocument是只读的。它

提供一种机制，可以检查 JSON值的结构内容，而无需自动实例化数据值。

因此，它并非旨在支持以任何方式修改JSON值，包括将另一个JSON值合并到其中。

当前存在一个增强请求，以实现可修改的JSON文档对象模型： Issue #39922: Writable Json DOM 。它具有关联的规范 Writable JSON Document Object Model (DOM) for System.Text.Json 。如果实施了此增强功能，则可以合并JSON文档。您可以添加一个要求与JContainer.Merge()等效的功能的问题，并作为前提条件链接回问题＃39922。

System.Text.Json合并两个对象

2 个答案: