Question

现在，有了android 10更新的权限和安全性，我们无法访问用户设备的设备ID和IMEI号，但我想要该设备的一些唯一ID，以便我们可以跟踪用户。

要求是我们要限制/限制一部手机的登录名

Answer 1

Android 10限制开发人员访问IMEI号码。

您可以通过获取软件ID获得替代解决方案。您可以将软件ID用作唯一ID。请在我在Application中使用以下代码。

公共静态字符串getDeviceId（上下文上下文）{

 String deviceId;

    if (android.os.Build.VERSION.SDK_INT >= Build.VERSION_CODES.Q) {
        deviceId = Settings.Secure.getString(
                context.getContentResolver(),
                Settings.Secure.ANDROID_ID);
    } else {
        final TelephonyManager mTelephony = (TelephonyManager) context.getSystemService(Context.TELEPHONY_SERVICE);
        if (mTelephony.getDeviceId() != null) {
            deviceId = mTelephony.getDeviceId();
        } else {
            deviceId = Settings.Secure.getString(
                    context.getContentResolver(),
                    Settings.Secure.ANDROID_ID);
        }
    }

    return deviceId;
}

Answer 2

由于序列号和 IMEI 号码已在 Android 10 及更高版本中弃用，因此，我们可以使用 READ_PRIVILEGED_PHONE_STATE 找到唯一标识符的 android id。

欲了解更多信息，请点击以下链接。 https://developer.android.com/training/articles/user-data-ids

Answer 3

getDeviceId() 自 API 级别 26 起已弃用。

“READ_PRIVILEGE_PHONE_STATE”只能被访问最佳实践建议您应该“避免使用硬件标识符”。用于唯一标识符。您可以使用来自 firebase 的实例 ID，例如 FirebaseInstanceId.getInstance().getId();

var model = compilation.GetSemanticModel(tree);
var methods = root.DescendantNodes().OfType<InvocationExpressionSyntax>();

foreach(var method in methods)
{
    if(model.GetSymbolInfo(method).Symbol is IMethodSymbol symbol &&
        symbol.ContainingNamespace.Name == "MyProject" &&
        symbol.ContainingType.Name == "LocalizationKeys" &&
        symbol.Name == "DefineKey")
    {
        var key = method.ArgumentList.Arguments.FirstOrDefault();
        var eng = method.ArgumentList.Arguments.Skip(1).FirstOrDefault();

        if(key.Expression is LiteralExpressionSyntax literalKey &&
            eng.Expression is LiteralExpressionSyntax literalEng)
        {
            // "/foo" -> "Hello World!"
            // "/bar" -> "Hello World2!"
            Console.WriteLine(literalKey + " -> " + literalEng);
        }
        else
        {
            // Bonus: detect violation of key definition rule. It is not a literal!
        }
    }
}

使用 FirebaseInstanceId.getInstance().getId(); 用于 Android 10 以上的 Api 级别

Answer 4

Android引入了一个新ID，用于唯一标识设备，称为 Advertisement_Id 。您可以从以下代码实现中的Application类 onCreate 方法中获取此ID。

/** Retrieve the Android Advertising Id 
     * 
     * The device must be KitKat (4.4)+ 
     * This method must be invoked from a background thread.
     * 
     * */
    public static synchronized String getAdId (Context context) {

        if (android.os.Build.VERSION.SDK_INT < android.os.Build.VERSION_CODES.KITKAT) {
            return null;
        }

        AdvertisingIdClient.Info idInfo = null;
        try {
            idInfo = AdvertisingIdClient.getAdvertisingIdInfo(context);
        } catch (GooglePlayServicesNotAvailableException e) {
            e.printStackTrace();
        } catch (GooglePlayServicesRepairableException e) {
            e.printStackTrace();
        } catch (IOException e) {
            e.printStackTrace();
        }
        String advertId = null;
        try{
            advertId = idInfo.getId();
        }catch (NullPointerException e){
            e.printStackTrace();
        }

        return advertId;
    }

对于Kotlin

     fun getAdId() {
        //Background Task
        AsyncTask.execute {
            var adInfo: AdvertisingIdClient.Info? = null
            try {
                adInfo = AdvertisingIdClient.getAdvertisingIdInfo(applicationContext)

                if(adInfo!=null){
                    val id = adInfo!!.getId()
                    val isLAT = adInfo!!.isLimitAdTrackingEnabled()

                    PersistData.setStringData(applicationContext, AppConstant.advertId, id)

                    val advertId = PersistData.getStringData(applicationContext, AppConstant.advertId)

                }

            } catch (e: IOException) {
                // Unrecoverable error connecting to Google Play services (e.g.,
                // the old version of the service doesn't support getting AdvertisingId).

            } catch (e: GooglePlayServicesAvailabilityException) {
                // Encountered a recoverable error connecting to Google Play services.

            } catch (e: GooglePlayServicesNotAvailableException) {
                // Google Play services is not available entirely.
            }


        }
    }

如何获取“ android 10+”设备的唯一设备ID？

4 个答案: