RxCocoa：无法使用类型为（（to：（UITapGestureRecognizer）-> Void）'

Question

我使用RxCocoa，我有这样的代码

func debug(){
        isUserInteractionEnabled = true
        let tap = UITapGestureRecognizer()
        tap.numberOfTapsRequired = 2
        addGestureRecognizer(tap)


        tap.rx.event.bind { (event) in

            if self.phone.text == Phone.one{
                self.phone.text = Phone.two
            }
            else{
                self.phone.text = Phone.one
            }
            self.verification.text = ""
        }.disposed(by: rx.disposeBag)

    }

我想做一些封装，将上面的内容变成这样：

func debug( _ event: (UITapGestureRecognizer) -> Void){


        isUserInteractionEnabled = true
        let tap = UITapGestureRecognizer()
        tap.numberOfTapsRequired = 2
        addGestureRecognizer(tap)
        tap.rx.event.bind(to: event).disposed(by: rx.disposeBag)

    }

Xcode报告：

  

无法使用类型为'（to：（UITapGestureRecognizer）-> Void）'的参数列表调用'bind'

我尝试

 func debug( _ event: @escaping (UITapGestureRecognizer) -> Void){

Xcode报告：

 Cannot invoke 'bind' with an argument list of type '(to: @escaping (UITapGestureRecognizer) -> Void)'

---

重要的是什么？ RX名称空间？

当我在前面键入event时，Xcode提示event是UITapGestureRecognizer

Answer 1

我认为bind(onNext: @escaping (E) -> Void)是您要找的，而不是bind<O: ObserverType>(to observer: O)。

比较实现方式

public func bind<O: ObserverType>(to observer: O) -> Disposable where O.E == E {
    return self.subscribe(observer)
}

public func bind(onNext: @escaping (E) -> Void) -> Disposable {
    return subscribe(onNext: onNext, onError: { error in
        rxFatalErrorInDebug("Binding error: \(error)")
    })
}