Question

我正在尝试在Laravel 5.2应用程序的全历4页面上从MySQL数据库导入数据。

我的Calendar.js文件：

import { Calendar } from '@fullcalendar/core';
import interactionPlugin from '@fullcalendar/interaction';
import dayGridPlugin from '@fullcalendar/daygrid';
import timeGridPlugin from '@fullcalendar/timegrid';
import frLocale from '@fullcalendar/core/locales/fr';
import bootstrapPlugin from '@fullcalendar/bootstrap';

document.addEventListener('DOMContentLoaded', function () {
    var calendarEl = document.getElementById('calendar');

    var calendar = new Calendar(calendarEl, {
        plugins: [interactionPlugin, dayGridPlugin, timeGridPlugin, bootstrapPlugin],
        // height: 'parent',
        aspectRatio: 1.5,
        themeSystem: 'bootstrap',
        locale: frLocale,
        header: {
            left: 'prev,next today',
            center: 'title',
            right: 'dayGridMonth,timeGridWeek,timeGridDay'
        },
        navLinks: true, // can click day/week names to navigate views
        editable: true,
        eventLimit: true,// allow "more" link when too many events
        events: 'getEvents',
    });
    calendar.render();
});

在“控制器”页面EventsController中的功能：

public function index(Request $request)
    {
        return view('front.events');
    }

public function getEvents()
    {
        $getEvents = Events::select('coach_id', 'start_date', 'end_date')->get();
        $events = [];

        foreach ($getEvents as $values) {
            $start_date_format = \DateTime::createFromFormat('Y-m-d h:i:s', $values->start_date);
            $end_date_format = \DateTime::createFromFormat('Y-m-d h:i:s', $values->end_date);
            $events ['title'] = $values->coach_id;
            $events ['start'] = $start_date_format->format('c');
            $events ['end'] = $end_date_format->format('c');
        }

        return $events;
    }

日历页面的路线部分：

Route::get('/events', 'EventsController@index')->name('events.index');
Route::get('/getEvents', 'EventsController@getEvents')->name('events.getEvents');

在这里查看events.twig：

{% extends 'front.layouts.main' %} {% set user = auth_user() %}
{% block css %}
    <link href='https://use.fontawesome.com/releases/v5.0.6/css/all.css' rel='stylesheet'>
{% endblock %}
{% set user = auth_user() %} {% block content %}

    <div class="container mb-5">
        <div class="response"></div>
        <div id='calendar'></div>
    </div>

{% endblock %}

{% block js %}
<script src="{{ asset('js/calendar.js') }}"></script>
{% endblock %}

我可以看到JSON格式正确的事件（当我加载页面getEvents时），但是日历页面中什么也没有出现。

我的JSON是这样的：

{"title":4,"start":"2019-10-23T11:00:00+00:00","end":"2019-10-23T12:00:00+00:00"}

我用JSON棉绒验证了它。

Answer 1

即使您只有一个事件，它也必须位于fullCalendar数组中才能识别它，例如

a {
    z-index: 99;
}

但是我认为您的PHP的逻辑是错误的-看起来它将遍历所有事件，但仍用循环中下一个事件的值覆盖$fontStyleName = 'oneUserDefinedStyle'; $phpWord->addFontStyle( $fontStyleName, array('name' => 'Asees', 'size' => 10.5, 'color' => '1B2232', 'bold' => true, 'spacing' => 13) ); $table->addCell(2000)->addText(htmlspecialchars("e[Zb oew ;w/s GST"), $fontStyleName);变量的属性。因此，即使您的数据库中有100个事件，它也将始终仅输出一个事件，并且在序列化为JSON时将始终是单个对象（而不是数组）。我认为您需要像这样更改它：

[{"title":4,"start":"2019-10-23T11:00:00+00:00","end":"2019-10-23T12:00:00+00:00"}]

这将在$events中为数据库中的每个记录创建一个事件，然后在创建新事件记录后将其添加到整个public function getEvents() { $getEvents = Events::select('coach_id', 'start_date', 'end_date')->get(); $events = []; foreach ($getEvents as $values) { $start_date_format = \DateTime::createFromFormat('Y-m-d h:i:s', $values->start_date); $end_date_format = \DateTime::createFromFormat('Y-m-d h:i:s', $values->end_date); $event = []; $event['title'] = $values->coach_id; $event['start'] = $start_date_format->format('c'); $event['end'] = $end_date_format->format('c'); $events[] = $event; } return $events; }列表中。

在FullCalendar 4中显示来自我的数据库的事件

1 个答案: