Question

我正在使用React native开发音乐播放器，并且一直在使用package react-native-track-player。到目前为止，我在android中没有遇到问题。但是当我尝试在ios上运行它时出现错误 You attempted to set the key 0 with the value

{"id":"0",
 "url":{"uri":"https://urltosong.mp3"},
 "artwork":"https://url_to_artwork.jpg",
 "artist":"author",
 "title":"song titile"
}

on an object that is meant to be immutable and has been frozen.

产生错误的代码是

async function togglePlayback() {
    const currentTrack = await TrackPlayer.getCurrentTrack();
    if (currentTrack == null) {
      await TrackPlayer.reset();
      await TrackPlayer.add(playlist); //this was never adding and die silently
      await TrackPlayer.play();
    } else {
            await TrackPlayer.add(playlist); //adding this line the error above appeared
            await TrackPlayer.play();
            //console.warn(TrackPlayer.getCurrentTrack())
    }
  }

我正在使用此版本的软件包"react-native-track-player": "^2.0.0-rc13", 我不知道我是否缺少什么。感谢您为解决此问题所提供的帮助。

Answer 1

将曲目更改为此：

{"id":"0",
 "url":"https://urltosong.mp3",
 "artwork":"https://url_to_artwork.jpg",
 "artist":"author",
 "title":"song titile"
}

网址应为string或Resource Object

React Native Track Player无法将歌曲添加到播放列表

1 个答案: