尝试使用Paffy获取YouTube播放列表的视频链接时出现错误

时间:2019-10-26 15:56:46

标签: python python-3.x pafy

import pafy
plurl = input("Enter The Link : ")
playlist = pafy.get_playlist(plurl)
l = len(playlist['author'])

#file = open("VideoInformation.txt","w+")

def extract_name_from_title(s):
c=0
name=""
start = s.find("-")
start = start+2
start = int(start)
end = s.find("|")
end = end-1
end = int(end)
name = s[start:end]

return name

for i in range(0,l-1) :
  id = playlist['items'][i]['pafy'].videoid
  v=pafy.new(id)
  #video = pafy.new('https://www.youtube.com/watch?v='+id)
  print("Video Number : {}".format(i))
  name = extract_name_from_title(v.title)
  link = "https://www.youtube.com/watch?v={}".format(id)
  print("Video title :{}".format(name))
  print("Video Link : {}".format(link))

IThis is the code and error window I am using **Spyder**

获得正确的输出后,显示错误列表 索引超出范围 谁能帮我避免该错误?

Youtube link I am using is:

1 个答案:

答案 0 :(得分:2)

只是在这里猜测,但是您可能希望将l = len(playlist['author'])更改为l = len(playlist['items']),因为要遍历播放列表项。