此表:
name | city
--------
john na
mary ny
mary in
是否存在返回所有记录和计数名称重复的查询?
查询结果:
name | count(name)
john 1
mary 2
mary 2
由于
答案 0 :(得分:2)
select o.name "Name",
(select count(*) from table_name i where i.name = o.name) "Count"
from table_name o;
答案 1 :(得分:1)
如果您的RDBMS支持窗口聚合函数。
SELECT name,
COUNT(*) OVER (PARTITION BY name)
FROM YourTable
答案 2 :(得分:0)
SELECT name,
COUNT(name) AS cnt
FROM table_name
GROUP BY name;