我们想在进行一些异步处理(例如网络进程)后显示AlertDialog。
当从外部类调用“ showAlertDialog()”时,我想在没有上下文的情况下调用它。有什么好方法吗?
class SplashPage extends StatelessWidget implements SplashView {
BuildContext _context;
@override
Widget build(BuildContext context) {
this._context = context;
...
}
我已经考虑过上述方法,但是我担心附带问题。
帮助
class SplashPage extends StatelessWidget implements SplashView {
@override
Widget build(BuildContext context) {
return Scaffold(
backgroundColor: MyStoreColors.eats_white1_ffffff,
body: Center(
child: new SvgPicture.asset('assets/ic_splash.svg'),
),
);
}
@override
void showAlertDialog() {
showDialog<void>(
context: /*How to get context?*/,
builder: (BuildContext context) {
return AlertDialog(
title: Text('Not in stock'),
content: const Text('This item is no longer available'),
actions: <Widget>[
FlatButton(
child: Text('Ok'),
onPressed: () {
Navigator.of(context).pop();
},
),
],
);
},
);
}
@override
void moveToHomeContainer() {
}
@override
void moveToLoginContainer() {
}
}
答案 0 :(得分:1)
答案 1 :(得分:0)
您应在异步事件完成后触发重建,将小部件转换为StatefulWidget
并调用setState()
或使用诸如Bloc之类的状态管理解决方案。
例如,使用StatefulWidget
,您的代码将如下所示:
class SplashPage extends StatefulWidget {
@override
State<SplashPage> createState() => _SplashPageState();
}
class _SplashPageState extends State<SplashPage> implements SplashView {
bool _asynOpDone = false;
/// Call this when the async operation is done.
void _onAsynOpDone() => setState(() => _asyncOpDone = true);
@override
Widget build(BuildContext context) {
if (_asyncOpDone) showAlertDialog(context);
return Scaffold(
...,
///
);
}
@override
void showAlertDialog(BuildContext context) {
showDialog<void>(
context: context,
builder: ...,
);
}
}