有没有办法基于特定列提取所有重复记录?

时间:2019-10-23 16:11:01

标签: unix awk ksh

我正在尝试从管道定界文件中提取所有(仅)重复值。

我的数据文件有80万行,其中包含多列,因此我对第3列特别感兴趣。因此,我需要获取第3列的重复值,并从该文件中提取所有重复的行。

我可以实现此目标,如下所示。

cat Report.txt | awk -F'|' '{print $3}' | sort | uniq -d >dup.txt

而我将以上内容视为循环,如下所示。

while read dup
do
   grep "$dup" Report.txt >>only_dup.txt
done <dup.txt

我也尝试过awk方法

while read dup
do
awk -v a=$dup '$3 == a { print $0 }' Report.txt>>only_dup.txt
done <dup.txt

但是,由于文件中包含大量记录,因此需要很长时间才能完成。因此,我正在寻找一种简便快捷的选择。

例如,我有这样的数据:

1|learning|Unix|Business|Requirements
2|learning|Unix|Business|Team
3|learning|Linux|Business|Requirements
4|learning|Unix|Business|Team
5|learning|Linux|Business|Requirements
6|learning|Unix|Business|Team
7|learning|Windows|Business|Requirements
8|learning|Mac|Business|Requirements

我的预期输出不包含唯一记录:

1|learning|Unix|Business|Requirements
2|learning|Unix|Business|Team
4|learning|Unix|Business|Team
6|learning|Unix|Business|Team
3|learning|Linux|Business|Requirements
5|learning|Linux|Business|Requirements

4 个答案:

答案 0 :(得分:3)

这可能是您想要的:

$ awk -F'|' 'NR==FNR{cnt[$3]++; next} cnt[$3]>1' file file
1|learning|Unix|Business|Requirements
2|learning|Unix|Business|Team
3|learning|Linux|Business|Requirements
4|learning|Unix|Business|Team
5|learning|Linux|Business|Requirements
6|learning|Unix|Business|Team

或者如果文件太大而无法容纳所有键($ 3值)(仅使用800,000行中的唯一$ 3值就不会有问题):

$ cat tst.awk
BEGIN { FS="|" }
{ currKey = $3 }
currKey == prevKey {
    if ( !prevPrinted++ ) {
        print prevRec
    }
    print
    next
}
{
    prevKey = currKey
    prevRec = $0
    prevPrinted = 0
}

$ sort -t'|' -k3,3 file | awk -f tst.awk
3|learning|Linux|Business|Requirements
5|learning|Linux|Business|Requirements
1|learning|Unix|Business|Requirements
2|learning|Unix|Business|Team
4|learning|Unix|Business|Team
6|learning|Unix|Business|Team

答案 1 :(得分:1)

EDIT2: 根据Ed先生的建议,我的建议使用更有意义的数组名称(IMO)进行了微调。

awk '
match($0,/[^\|]*\|/){
  val=substr($0,RSTART+RLENGTH)
  if(!unique_check_count[val]++){
    numbered_indexed_array[++count]=val
  }
  actual_valued_array[val]=(actual_valued_array[val]?actual_valued_array[val] ORS:"")$0
  line_count_array[val]++
}
END{
  for(i=1;i<=count;i++){
    if(line_count_array[numbered_indexed_array[i]]>1){
      print actual_valued_array[numbered_indexed_array[i]]
    }
  }
}
'  Input_file

埃德·莫顿(Ed Morton)编辑:FWIW这是我在上面的代码中命名变量的方式:

awk '
match($0,/[^\|]*\|/) {
  key = substr($0,RSTART+RLENGTH)
  if ( !numRecs[key]++ ) {
    keys[++numKeys] = key
  }
  key2recs[key] = (key in key2recs ? key2recs[key] ORS : "") $0
}
END {
  for ( keyNr=1; keyNr<=numKeys; keyNr++ ) {
    key = keys[keyNr]
    if ( numRecs[key]>1 ) {
      print key2recs[key]
    }
  }
}
' Input_file


编辑: :由于OP用|分隔了Input_file,因此将代码更改如下,从而处理了新的Input_file(感谢Ed Morton先生指出来)。

awk '
match($0,/[^\|]*\|/){
  val=substr($0,RSTART+RLENGTH)
  if(!a[val]++){
    b[++count]=val
  }
  c[val]=(c[val]?c[val] ORS:"")$0
  d[val]++
}
END{
  for(i=1;i<=count;i++){
    if(d[b[i]]>1){
      print c[b[i]]
    }
  }
}
'   Input_file


请尝试以下操作,以下操作将按输入文件中出现行的相同顺序给出输出。

awk '
match($0,/[^ ]* /){
  val=substr($0,RSTART+RLENGTH)
  if(!a[val]++){
    b[++count]=val
  }
  c[val]=(c[val]?c[val] ORS:"")$0
  d[val]++
}
END{
  for(i=1;i<=count;i++){
    if(d[b[i]]>1){
      print c[b[i]]
    }
  }
}
'  Input_file

输出如下。

2 learning Unix Business Team
4 learning Unix Business Team
6 learning Unix Business Team
3 learning Linux Business Requirements
5 learning Linux Business Requirements

上述代码的说明:

awk '                                 ##Starting awk program here.
match($0,/[^ ]* /){                   ##Using match function of awk which matches regex till first space is coming.
  val=substr($0,RSTART+RLENGTH)       ##Creating variable val whose value is sub-string is from starting point of RSTART+RLENGTH value to till end of line.
  if(!a[val]++){                      ##Checking condition if value of array a with index val is NULL then go further and increase its index too.
    b[++count]=val                    ##Creating array b whose index is increment value of variable count and value is val variable.
  }                                   ##Closing BLOCK for if condition of array a here.
  c[val]=(c[val]?c[val] ORS:"")$0     ##Creating array named c whose index is variable val and value is $0 along with keep concatenating its own value each time it comes here.
  d[val]++                            ##Creating array named d whose index is variable val and its value is keep increasing with 1 each time cursor comes here.
}                                     ##Closing BLOCK for match here.
END{                                  ##Starting END BLOCK section for this awk program here.
  for(i=1;i<=count;i++){              ##Starting for loop from i=1 to till value of count here.
    if(d[b[i]]>1){                    ##Checking if value of array d with index b[i] is greater than 1 then go inside block.
      print c[b[i]]                   ##Printing value of array c whose index is b[i].
    }
  }
}
'  Input_file                         ##Mentioning Input_file name here.

答案 2 :(得分:1)

另一个awk:


describe('Create a new entry', () => {
    it('Should return a success: new entry created', (done) => {
        const testEntry1= {
            title: 'My title',
            description: 'My description'
        };
        process.env.TOKEN ="the token";
        chai.request(app).post('/api/v1/entry')
            .set(process.env.TOKEN)
            .send(testEntry1) 
            .end((err, res) => {
                expect(res).to.have.status(201);
                expect(res.body.data).to.be.a('object');
            });
        done();
    });
});

示例数据的输出:

$ awk -F\| '{                  # set delimiter
    n=$1                       # store number
    sub(/^[^|]*/,"",$0)        # remove number from string
    if($0 in a) {              # if $0 in a
        if(a[$0]==1)           # if $0 seen the second time
            print b[$0] $0     # print first instance
        print n $0             # also print current
    }
    a[$0]++                    # increase match count for $0
    b[$0]=n                    # number stored to b and only needed once
}' file

还可以吗?

2|learning|Unix|Business|Team
4|learning|Unix|Business|Team
3|learning|Linux|Business|Requirements
5|learning|Linux|Business|Requirements
6|learning|Unix|Business|Team

$ sort -k 2 file | uniq -D -f 1 或smth。 不,因为分隔符从空间更改为管道。

答案 3 :(得分:0)

两步改进。
第一步:
之后

awk -F'|' '{print $3}' Report.txt | sort | uniq -d >dup.txt
# or
cut -d "|" -f3 < Report.txt | sort | uniq -d >dup.txt

您可以使用

grep -f <(sed 's/.*/^.*|.*|&|.*|/' dup.txt) Report.txt
# or without process substitution
sed 's/.*/^.*|.*|&|.*|/' dup.txt > dup.sed
grep -f dup.sed Report.txt

第二步:
按照其他更好的答案中的方法使用awk