如何在SwiftUI中使用带有条件检查的按钮进行导航

时间:2019-10-23 14:32:47

标签: navigation swiftui navigationlink

由于 NavigationButton 不再可用,如何在 NavigationLink 中检查条件以导航到另一个视图?


NavigationLink(destination: Dashboard(userName: self.userId, 
                                      password: self.password), isActive: $showDashboard) {

                    Button(action: {
                        if self.userId.isEmpty || self.password.isEmpty {
                            self.isAlert = true
                        } else {
                            self.showDashboard = true
                        }

                    }) {
                        Text("Submit")
                            .foregroundColor(.white)
                            .font(.system(size: 22))

                        Dashboard()
                    }
                    .frame(minWidth: 150, idealWidth: 300, maxWidth: 450, 
                     minHeight: 30, idealHeight: 40, maxHeight: 50, alignment: .center)
                    .background(Color(red: 81/255, green: 221/255, blue: 182/255))

                    .padding([.leading, .trailing], 20)
                } 

编辑:-

如果 userName password 的长度大于16,我还想显示警报;如果长度大于10,则显示其他警报;如果长度为0,则显示空消息警报

2 个答案:

答案 0 :(得分:0)

您可以执行以下操作:

    NavigationView {
        VStack {
            NavigationLink(destination:  Dashboard(userName: self.userId, password: self.password), isActive: $showDashboard) {
                Text("")
            }
            Button(action: {
                 if self.userId.isEmpty || self.password.isEmpty {
                      self.isAlert = true
                  } else {
                      self.showDashboard = true
                  }
            }) {
                Text("Submit")
                    .foregroundColor(.green)
                    .font(.system(size: 22))

            }
        }
    }

要记住的一点是,NavigationLink本身就是一个按钮,当按下它导航到destinationView时,isActive参数是强制执行此操作的一种方式(无需用户单击NavigationLink )。到目前为止,我不确定如何将逻辑嵌入到NavigationLinks中。

希望这会有所帮助:)

编辑:

您可以做的另一件事是

NavigationLink(destination:Dashboard(userName: self.userId, password: self.password)) {
                    Text("Submit")
                }.disabled(self.userId.isEmpty || self.password.isEmpty )

这将禁用NavigationLink,直到两个输入字段都不为空。

答案 1 :(得分:0)

我不确定您是否要检查条件以确定NavigationLink的目的地,或者是否将其禁用,但是此示例代码显示了如何执行这两项操作:

struct ContentView: View {
    @State var userId = ""
    @State var password = ""

    var body: some View {
        NavigationView {
            NavigationLink(destination: (self.userId.isEmpty || self.password.isEmpty) ? AnyView(Dashboard(userName: self.userId, password: self.password)) : AnyView(Text("Different view")), isActive: Binding(get: {
                return self.userId.isEmpty || self.password.isEmpty
            }, set: { (_) in

            })) {
                Text("Navigate")
            }
        }
    }
}

isActive创建自定义绑定以评估多种情况:

Binding(get: {
        return self.userId.isEmpty || self.password.isEmpty
}, set: { (_) in

})

然后评估ternary statement中的条件,如果希望条件确定AnyView导航到哪个视图,请确保对类型to return different kinds of views使用NavigationLink

(self.userId.isEmpty || self.password.isEmpty) ? AnyView(Dashboard(userName: self.userId, password: self.password) : AnyView(Text("Different view"))

编辑:如果不希望条件转换为nil,则可以将另一个视图设置为false

(self.userId.isEmpty || self.password.isEmpty) ? AnyView(Dashboard(userName: self.userId, password: self.password) : nil

编辑2 :如果您希望在条件失败时显示警报,请使用上一行(带有nil)作为NavigationLink的目的地,并添加一个警报Binding的自定义isPresented

.alert(isPresented: Binding(get: {
            return self.userId.isEmpty || self.password.isEmpty
    }, set: { (_) in

    })) {
        Text("Alert message")
    }

您可以使用要评估的变量(在本例中为ContentView)将此警报添加到视图的任何子视图中。