通过Google脚本从Google Sheet向Telegram发送消息

时间:2019-10-21 04:13:27

标签: javascript json google-apps-script google-sheets-api telegram-bot

我每天早晨都在尝试向自己发送电报消息,并使用Google表格中列出的其他报价。我编写了一些将消息添加到列表的代码,但是似乎无法从列表中生成随机行以每天发送。

var token = "TOKEN"; 
var telegramAPI = "https://api.telegram.org/bot" + token; 
var webAppAPI = "https://script.google.com/macros/s/GOOGLE_WEB_APP_ADDRESS";
var ssId = "SPREADSHEET_ID"; 

function getMe() {
  var url = telegramAPI + "/getMe";
  var response = UrlFetchApp.fetch(url);
  Logger.log(response.getContentText());
}

function setWebhook() {
  var url = telegramAPI + "/setWebhook?url=" + webAppAPI;
  var response = UrlFetchApp.fetch(url);
  Logger.log(response.getContentText());
}

function sendText(id,text) {
  var url = telegramAPI + "/sendMessage?chat_id=" + id + "&text=" + text;
  var response = UrlFetchApp.fetch(url);
  Logger.log(response.getContentText());
}

function doGet(e) {
  return HtmlService.createHtmlOutput("Test Data" + JSON.stringify(e,null,4));
}

function doPost(e) {
  Logger.log(e);  
  var data = JSON.parse(e.postData.contents);
  var text = data.message.text;
  var what = data.message.text.split("-")[0]
  var who = data.message.text.split("-")[1]
  var id = data.message.chat.id;
  var name = data.message.chat.first_name;
  var response = "Hi " + name + ", this quote has been added to your database: " + text;
  sendText(id,response);
  SpreadsheetApp.openById(ssId).getSheets()[1].appendRow([new Date(),id,name,text,response,what,who]);

所有这些都很好。我添加了一个查询,将其从“电报摘要”工作表中拉到“报价”工作表,我将在此处帮助他人:

=IFERROR(QUERY('Telegram Feed'!$G$1:$G$98,"",-1),"Error")

现在我要引用报价,我想从列表中生成一个随机的报价,并安排它每天发送给自己。我在下面列出了我尝试过的内容,但似乎无法弄清楚自己在做错什么。

随机化器部分起作用,但似乎正在获取所有内容,我需要重构这些内容以表达以下内容:

message = f"{quote} + ' - ' + {author}"

随机化器:

function randomizer() {
  var ssa = SpreadsheetApp.openById(ssId);
  var ss = ssa.getSheetByName('Quotes'); 
  var range = ss.getRange(1,1,ss.getLastRow(), 2);
  var data = range.getValues();

  for(var i = 0; i < data.length; i++) 
  { 
    var j = Math.floor(Math.random()*(data[i].length));
    var element = data[i][j]; 
    ss.getRange(i+1, 6).setValue(element); 
    Logger.log(element);
  }
}  

到现在为止,它大部分都可以正常工作(尽管我如上所述需要弄清楚如何修复随机化器功能。这是当我尝试从脚本向Telegram发送随机消息时遇到问题。< / p>

function sendQuote(what,who) {
  var data = randomizer();
  var dataJSON = JSON.parse(data.postData.contents);
  var url = telegramAPI + "/sendMessage?chat_id=" + 'CHAT_ID_NUM' + "&text=" + what + " - " who;
} 

我什么也没回来。有人知道我在做什么错吗?

编辑:

我遵循了Дмитро-Булах和carlesgg97的建议,并且重构了我的一些随机代码,为我提供了报价和作者。由于某种原因,我现在从读取var dataJSON = JSON.parse(data.postData.contents);

的行中收到错误“ TypeError:无法从未定义的属性中读取属性“ postData” 。:

有人知道为什么会这样吗? 无论如何,我会在24小时内解决问题。谢谢大家的帮助!

function sendQuote(quote,author) {
  var data = randomize();
  var dataJSON = JSON.parse(data.postData.contents);
  var encodedText = encodeURIComponent(quote + " - " + author);
  var url = telegramAPI + "/sendMessage?chat_id=" + 'CHAT_ID' + "&text=" + encodedText;
  UrlFetchApp.fetch(url);
} 

function randomize() {
  var sss = SpreadsheetApp.openById(ssId);
  var ss = sss.getSheetByName('Quotes');

  var length = ss.getLastRow();
  var overshoot = 97 //monitor for changes as list size increases
  var true_length = length-overshoot;   
  var line = (Math.random() * ((true_length - 2) + 1)) + 2;

  var quote_cell = ss.getRange(line,2);
  var quote = quote_cell.getValue();
  var author_cell = ss.getRange(line,1);
  var author = author_cell.getValue();
  Logger.log(quote + " - " + author);
}

1 个答案:

答案 0 :(得分:1)

似乎您可能遇到两个不同的问题:

  1. 您没有将文本编码为URL安全。要将数据(在这种情况下为text URL查询字符串参数)安全地附加到URL,您应该使用encodeURIComponent()
  2. 您似乎实际上并未发送请求。您是否错过了UrlFetchApp.fetch()通话?

请参见下面的示例来解决这两个问题:

function sendQuote(what,who) {
  var data = randomizer();
  var dataJSON = JSON.parse(data.postData.contents);
  var encodedText = encodeURIComponent(what + " - " + who);
  var url = telegramAPI + "/sendMessage?chat_id=" + 'CHAT_ID_NUM' + "&text=" + encodedText;
  UrlFetchApp.fetch(url);
}