Question

这是我们的对象：

let obj = {
  "I was sent":  ["I was sent", "I was forced"],
  "to earth": ["to earth", "to moon"],
  "to protect you": [ "to find you", "to protect you", "to love you"]

}

我想根据属性名称将数组元素移动到数组的末尾。

所需的结果将是：

  let obj = {
      "I was sent":  ["I was forced", "I was sent"],
      "to earth": ["to moon", "to earth"],
      "to protect you": [ "to find you", "to love you", "to protect you"]

    }

Answer 1

使用Object.entries()将对象转换为[键，值]对的数组。映射数组，并针对每对，检查键（k）在值（v）中的索引。如果找到索引，请将键移到值的末尾。通过Object.fromEntries()将数组转换回对象。

const obj = {
  "I was sent":  ["I was sent", "I was forced"],
  "to earth": ["to earth", "to moon"],
  "to protect you": [ "to find you", "to protect you", "to love you"]
}

const result = Object.fromEntries(Object.entries(obj)
  .map(([k, v]) => {
    const index = v.findIndex(s => s === k)
    
    return [
      k,
      index > -1 ? [...v.slice(0, index), ...v.slice(index + 1), k] : v
    ]
  }))
  
console.log(result)

如果始终在值中找到键，则可以始终对其进行过滤，并将其添加到数组的末尾：

const obj = {
  "I was sent":  ["I was sent", "I was forced"],
  "to earth": ["to earth", "to moon"],
  "to protect you": [ "to find you", "to protect you", "to love you"]
}

const result = Object.fromEntries(Object.entries(obj)
  .map(([k, v]) => {
    const newV = [...v.filter(s => s !== k), k]
    
    return [k, newV]
  }))
  
console.log(result)

如何将对象内的数组元素移动到数组的末尾

1 个答案: