Question

如果有人有经验，这个问题与HECRAS有关，但总的来说，这只是关于将文本文件写入非常特殊的格式以供HECRAS软件读取的问题。

基本上，我正在读取一些文件并更改一些数字，然后将其写回，但我似乎无法完全匹配初始格式。

原始文件的外观如下：

Type RM Length L Ch R = 1 ,229.41  ,21276,21276,21276
Node Last Edited Time=Oct-17-2019 15:52:28
#Sta/Elev= 452 
       0  20.097  67.042   9.137   67.43   9.139  68.208   9.073  68.598   9.129
  68.986   9.086  70.538   9.071  70.926   9.042  71.984   9.046   72.48   9.025
  73.646   9.056  74.368   9.034  75.586   9.042   76.55   9.017  77.138   9.047
  78.304   8.989   79.47   9.025   80.19   9.001   81.41   9.003  81.974   8.978
   83.83   9.005  85.284   9.079  85.682   9.068   86.97   9.118  88.012   9.223
   88.79   9.239   89.65   9.316  90.342   9.324  91.134   9.475  91.966   9.525
  92.282   9.589  93.346   9.546  94.222   9.557  94.922   9.594   95.71   9.591
  96.546    9.64  97.286   9.574   98.87   9.688  99.258   9.673  99.642   9.712
#Mann= 3 , 0 , 0 
       0     .09       0   246.4    .028       0   286.4     .09       0
Bank Sta=246.4,286.4
XS Rating Curve= 0 ,0
XS HTab Starting El and Incr=1.708,0.1, 500 
XS HTab Horizontal Distribution= 5 , 5 , 5 
Exp/Cntr=0.3,0.1

我对Sta / Elev数据感兴趣...看起来像是一些右对齐的制表符/空格？分隔格式，每行每行5个站点/高度对。也许每对16个字符？

我尝试了很多不同的事情，我当前的代码是：

with open('C:/Users/deden/Desktop/t/test.g01','w') as out:
    out.write(txt[:idx[0][0]])
    out.write(txt[idx[0][0]:idx[0][0]+bounds[0]])
    out.write('#'+raw_SE.split('\n')[0]+'\n')
    i = 0 
    while i <= len(new_SE):
        out.write('\t'.join(new_SE[i:i+10])+'\n')
        i+=10
    out.write(txt[idx[0][0]+bounds[1]:idx[1][0]])

这是一个有点笨拙的atm，仍在设法解决，重要的部分是：

while i <= len(new_SE):
    out.write('\t'.join(new_SE[i:i+10])+'\n')
    i+=10

new_SE只是桩号/高度的列表：

['0', '30.097', '67.042', '19.137', '67.43', '19.139', '68.208', '19.073', '68.598', '19.128999999999998' ...]

我也尝试过用类似的东西玩：

'%8s  %8s' % (tmp[0], tmp[1])

基本上在文本之间有8个空格，但右对齐它们

诚实地奋斗...如果有人可以在＃Sta / Elev = 452和#Mann之间重新创建原始文本，我将非常感激，如果有人想尝试一下，这里是完整列表：

new_SE = ['0', '30.097', '67.042', '19.137', '67.43', '19.139', '68.208', '19.073', '68.598', '19.128999999999998', '68.986', '19.086', '70.538', '19.070999999999998', '70.926', '19.042', '71.984', '19.046', '72.48', '19.025', '73.646', '19.055999999999997', '74.368', '19.034', '75.586', '19.042', '76.55', '19.017', '77.138', '19.047', '78.304', '18.989', '79.47', '19.025', '80.19', '19.000999999999998', '81.41', '19.003', '81.974', '18.978', '83.83', '19.005000000000003', '85.284', '19.079', '85.682', '19.067999999999998', '86.97', '19.118000000000002', '88.012', '19.223', '88.79', '19.239', '89.65', '19.316000000000003', '90.342', '19.323999999999998', '91.134', '19.475', '91.966', '19.525', '92.282', '19.589', '93.346', '19.546', '94.222', '19.557000000000002', '94.922', '19.594', '95.71', '19.591', '96.546', '19.64', '97.286', '19.573999999999998', '98.87', '19.688000000000002', '99.258', '19.673000000000002', '99.642', '19.712']

Answer 1

不确定我是否正确理解-请考虑看看

# with open('C:/Users/deden/Desktop/t/test.g01','w') as out:
    for i in range(0, len(new_SE), 10):
        row = [f'{float(v):8.3f}' for v in new_SE[i:i+10]]
        out.write(''.join(r) + '\n')

#    0.000  30.097  67.042  19.137  67.430  19.139  68.208  19.073  68.598  19.129
#   68.986  19.086  70.538  19.071  70.926  19.042  71.984  19.046  72.480  19.025
#   73.646  19.056  74.368  19.034  75.586  19.042  76.550  19.017  77.138  19.047
#   78.304  18.989  79.470  19.025  80.190  19.001  81.410  19.003  81.974  18.978
#   83.830  19.005  85.284  19.079  85.682  19.068  86.970  19.118  88.012  19.223
#   88.790  19.239  89.650  19.316  90.342  19.324  91.134  19.475  91.966  19.525
#   92.282  19.589  93.346  19.546  94.222  19.557  94.922  19.594  95.710  19.591
#   96.546  19.640  97.286  19.574  98.870  19.688  99.258  19.673  99.642  19.712

需要帮助确定文本文件中文本的一般格式

1 个答案: