如何创建获取服务以从JIRA检索冲刺报告?有人可以帮助我完成图片中的第二步吗?

时间:2019-10-17 16:03:07

标签: java spring spring-boot jira-rest-api jira-rest-java-api

https://ibb.co/Rjhwzfm

所以我必须创建一个获取服务以使用JIRA rest api从JIRA检索sprint报告(基本上是数据),到目前为止,已经在springboot中使用REST模板完成了此操作

SpringBootApplication.java


import org.springframework.boot.SpringApplication;
import org.springframework.boot.autoconfigure.SpringBootApplication;

import org.slf4j.Logger;
import org.slf4j.LoggerFactory;
import org.springframework.boot.CommandLineRunner;
import org.springframework.boot.SpringApplication;
import org.springframework.boot.autoconfigure.SpringBootApplication;
import org.springframework.boot.web.client.RestTemplateBuilder;
import org.springframework.context.annotation.Bean;
import org.springframework.web.client.RestTemplate;

@SpringBootApplication
public class SprintBootApplication {

private static final Logger log = LoggerFactory.getLogger(SprintBootApplication.class);

public static void main(String args[]) {
 SpringApplication.run(SprintBootApplication.class);
}

@Bean
public RestTemplate restTemplate(RestTemplateBuilder builder) {
 return builder.build();
}

@Bean
public CommandLineRunner run(RestTemplate restTemplate) throws Exception {
 return args -> {
  JiraDataFields data = restTemplate.getForObject(
    "https://jira.mtvi.com/rest/api/2/search?fields=issuetype,customfield_10280,parent,key,summary,status,timeestimate,aggregatetimeoriginalestimate,assignee,subtasks&jql=project", JiraDataFields.class);
  log.info(data.toString());
 };
}
}```

JiraDataFields.class

```package com.sprint.SprintBoot;

public class JiraDataFields {

private int id;
private String workedBy;


}```

0 个答案:

没有答案