我尝试嵌套一条路线:我在 Catalog 组件中有一个产品目录,与URL “ backoffice / catalog” 匹配。
如果URL与“ backoffice / catalog / edit” 匹配,我想路由到 Edition 组件,但是我需要 Edition 组件成为目录的孩子以分享道具。
我真的不明白为什么嵌套路线不起作用,请救救我!而且不要犹豫告诉我我的应用程序是否有任何问题,我非常了解Javascript,但是我从React:D
开始这是我的App组件:
import React from "react";
import { Route, Switch } from "react-router-dom";
import { Home } from "./components/Static/Home.js";
import { Dashboard } from "./components/Backoffice/Dashboard.js";
import { Catalog } from "./components/Backoffice/catalog/Catalog.js";
import { Login } from "./components/Login/Login.js";
import { Signup } from "./components/Signup/Signup.js";
import { PrivateRoute } from "./components/PrivateRoute.js";
import "./scss/App.scss";
import {Header} from "./components/Structure/Header";
import {BOHeader} from "./components/Structure/Backoffice/Header";
import {List} from "./components/Listing/List";
function App()
{
return (
<div className="App">
<div className="App-content">
<Switch>
<Route path='/backoffice' component={BOHeader} />
<Route path='/' component={Header} />
</Switch>
<Switch>
<Route exact path='/' component={Home} />
<Route exact path='/login' component={Login} />
<Route exact path='/signup' component={Signup} />
<Route path='/listing' component={List}/>
<PrivateRoute exact path='/backoffice' component={Dashboard}/>
<PrivateRoute exact path='/backoffice/catalog' component={Catalog}/>
</Switch>
</div>
</div>
);
}
export default App;
这是我的目录组件(路由是通过render方法创建的:
import React from 'react';
import Data from '../../../Utils/Data';
import {Product} from './Product';
import {Edition} from './Edition';
import {
BrowserRouter as Router,
Switch,
Route,
Link,
useRouteMatch,
useParams
} from "react-router-dom";
export class Catalog extends React.Component
{
state = {
title: '',
products: [],
editionProduct: null
};
obtainProducts = () =>
{
Data.products.obtain()
.then(products => {this.setState({products: products});})
};
editProductHandler = product =>
{
this.setState({editionProduct: product});
};
saveProductHandler = product =>
{
Data.products.save(product).then(() => {
this.state.products.map(item => {
item = item._id === product._id ? product : item;
return item;
})
});
};
deleteProductHandler = event =>
{
const productId = event.target.closest('.product-actions').dataset.productid;
let products = this.state.products.filter(product => {
return product._id !== productId;
});
this.setState({products: products}, () => {
Data.products.remove(productId);
});
};
displayProducts = () =>
{
return this.state.products.map(product => {
return (
<li key={product._id} className='catalog-item'>
<Product
deleteProductHandler={this.deleteProductHandler}
editProductHandler={this.editProductHandler}
data={product}
/>
</li>
)
});
};
componentWillMount()
{
this.obtainProducts();
}
render() {
const Products = this.displayProducts();
let { path, url } = useRouteMatch();
return (
<div className={this.state.editionProduct ? 'catalog edit' : 'catalog'}>
<h1>Catalog</h1>
<Switch>
<Route exact path={path}>
<ul className='catalog-list'>{Products}</ul>
</Route>
<Route path={`${path}/edit`}>
<Edition saveProductHandler={this.saveProductHandler} product={this.state.editionProduct} />
</Route>
</Switch>
</div>
);
}
}
有什么想法吗?
答案 0 :(得分:5)
您不能在Catalog
组件内使用钩子,因为它是一个类组件。因此,您有两种方法可以解决问题:
useRouteMatch
。如果需要在组件内部获取Catalog
数据,则需要使用withRouter
高阶组件。因此,如果您选择第二种方法,则需要将match
组件包装在Catalog
中:
withRouter
在export default withRouter(Catalog);
函数中从以下位置更改一行:
render
收件人:
let { path, url } = useRouteMatch();
也不要忘记更改const { path, url } = this.props.match;
组件的导入,因为现在您的组件将默认导出。
答案 1 :(得分:4)
由于使用Typescript设置React Router时遇到了相同的问题,因此我将分4个步骤详细介绍Andrii答案:
yarn add react-router-dom --save
yarn add @types/react-router-dom --save-dev
或
npm install react-router-dom --save
npm install @types/react-router-dom --save-dev
1)导入高阶组件(在当前情况下为App)时,请勿使用大括号,因为App将默认导出;
2)BrowserRouter需要处于较高级别,而不是将作为“ default withRouter(Class)”导出的类,以防止出现以下错误:
“您不应在路由器外部使用Route或withRouter()”
import React from 'react';
import ReactDOM from 'react-dom';
import { BrowserRouter } from 'react-router-dom';
import * as serviceWorker from './serviceWorker';
import App from './app';
ReactDOM.render(
<BrowserRouter>
<App />
</BrowserRouter>,
document.getElementById('root')
);
serviceWorker.unregister();
1)使用路由器和RouteComponentProps(或您自己的PropType定义)从 react-router-dom 导入;
2)扩展React.Component并使用RouteComponentProps接口;
3)将道具传递到要共享路由数据的组件;
4)使用路由器将高阶类导出为默认值。
import React, { ReactElement } from 'react';
import { Switch, Route, withRouter, RouteComponentProps } from 'react-router-dom';
import { ExpensesPage } from './pages/expenses/expenses.page';
import { HomePage } from './pages/home/home.page';
import { HeaderComponent } from './components/header/header.component';
import './app.scss';
class App extends React.Component<RouteComponentProps> {
public render(): ReactElement {
return (
<div className='playground'>
<HeaderComponent {...this.props} />
<div className="playground-content">
<Switch>
<Route exact path='/' component={HomePage} {...this.props} />
<Route exact path='/expenses' component={ExpensesPage} {...this.props} />
</Switch>
</div>
</div>
);
}
}
export default withRouter(App);
通过RouteComponentProps扩展类,您通常可以以历史记录,位置和下面的方式访问路由道具:
import React, { ReactElement } from 'react';
import { RouteComponentProps } from 'react-router-dom';
import './header.component.scss';
export class HeaderComponent extends React.Component<RouteComponentProps> {
public render(): ReactElement {
const { location } = this.props;
console.log(location.pathname);
return (
<header className="header">
{/* ... */}
</header >
);
}
}
希望它会有所帮助,因为要使它在具有webpack且没有redux的简单环境中进行工作有一点挑战。上一次可在以下版本上正常使用:
{
"react": "^16.12.0",
"react-dom": "^16.12.0",
"react-router-dom": "^5.1.2",
"sass-loader": "^8.0.2",
"style-loader": "^1.1.3",
"typescript": "^3.8.2",
"webpack": "^4.41.6",
"webpack-dev-server": "^3.10.3",
},
{
"@types/react-router-dom": "^5.1.3",
"webpack-cli": "^3.3.11"
}