我有一个具有此内容的表(有更多不相关的字段):
交易可以是购买或出售。购买可以是id_factura或id_albaran,如果购买的是id_factura,id_albaran为Null,反之亦然,则销售额相同。但是销售可以有两个具有相同imei的记录,如我们在示例中看到的:id_purchasesale 2和3(在这种情况下,它将始终具有相同的价格,在示例250中)。
imei字段只能作为一次购买(发票_id或albaran_id)存在,或者作为一次或两次销售存在。
如果有购买但没有出售相同的imei,则不必出示它。
表购买
id_purchasesale transaction id_factura id_albaran Model imei price
1 purchase 1 Null Samsung 30888 200
2 sale 1 Null Samsung 30888 250
3 sale Null 1 Samsung 30888 250
4 purchase Null 1 Apple 52101 300
5 sale 1 Null Apple 52101 380
6 purchase 2 Null Motorola 77520 300
7 sale 2 Null Motorola 77520 350
8 purchase 3 Null Xiaomi 29102 150
我想要获得的结果如下:一个带有购买价格的字段,另一个带有销售价格的字段,另一个带有这两个字段和模型字段的利润的字段。
imei price_purchase price_sale profit Model
30888 200 250 50 Samsung
52101 300 380 80 Apple
77520 300 350 50 Xiaomi
答案 0 :(得分:1)
您可以在下面尝试-
select imeid,
max(case when transaction='purchase' then price else 0 end) as purchase_price,
max(case when transaction='sale' then price else 0 end) as sale_price,
max(case when transaction='sale' then price else 0 end)-max(case when transaction='purchase' then price else 0 end) as profit,
model
from tablename
where transaction in ('purchase','sale')
group by imeid,model
having count(distinct transaction)=2
答案 1 :(得分:1)
您可以使用同一张表,两个使用别名并按买卖进行过滤
select a.imei
, a.model
, a.price as price_purchase
, b.price as price_sale
, b.price - a.price as profit
from purchasesale a
inner join purchasesale b on a.imei = b.imei
and a.transaction ='purchase'
and b.transaction ='sale'
答案 2 :(得分:1)
您的餐桌设计一团糟。如果可以更改它,我会将此表分为三个单独的表,一个用于购买,一个用于销售,另一个用于电话。
但是,在当前情况下,这应该可以满足您的要求:
SELECT
t1.imei as imei,
t1.price as price_purchase,
t2.price as price_sale,
(t2.price - t1.price) as profit,
t1.model as model
FROM purchasesale t1, purchasesale t2
WHERE t1.imei = t2.imei and
t1.transaction = 'purchase' and
t2.transaction = 'sale'
希望我能帮上忙!