Question

<?php
function saveFile($url, $filename) {
    $data = file_get_contents($url);
    $fh = fopen($filename, 'w') or die("can't open file");
    fwrite($fh, $data);
    fclose($fh);
}
$myFile = "images.txt";
$fh = fopen($myFile, 'r');
$theData = fread($fh, filesize($myFile));
$data = explode("\n", $theData);

$count = count($data);

for($i=0;$i<=$count;$i++) {

    saveFile($data[$i], basename($data[$i]));
}

?>

这是我的代码，每次我更换动态文件名时都会输出错误

Warning: fopen(10017226314.jpg ) [function.fopen]: failed to open stream: Invalid argument in C:\xampp\htdocs\download\download.php on line 4
can't open file

原因应该是什么？请帮忙。感谢

Answer 1

请将您的fopen函数参数从w替换为r+

function saveFile($url, $filename) {
    $data = file_get_contents($url);
    $fh = **fopen($filename, 'r+')** or die("can't open file");
    fwrite($fh, $data);
    fclose($fh);
}

php下载文件，阅读问题

1 个答案: