我有一个let json = [
{
"metadata": {
"id": "vvvvvvvvvvvvv",
"url": "cccccccccccccc",
"created_at": "2019-09-06T08:40:41Z",
"updated_at": "2019-09-06T13:25:46Z"
},
"entity": {
"name": "app1",
"b_enabled": false,
"d_url": "xxxxxs"
}
},
{
"metadata": {
"id": "vvvvvvvvvvccc",
"url": "cccccccccccccc",
"created_at": "2019-09-06T08:40:41Z",
"updated_at": "2019-09-06T13:25:46Z"
},
"entity": {
"name": "app2",
"b_enabled": false,
"d_url": "xxxxxs"
}
},
{
"metadata": {
"id": "vvvvvvvvvvddd",
"url": "cccccccccccccc",
"created_at": "2019-09-06T08:40:41Z",
"updated_at": "2019-09-06T13:25:46Z"
},
"entity": {
"name": "app3",
"b_enabled": false,
"d_url": "xxxxxs"
}
},
{
"metadata": {
"id": "vvvvvvvvvveee",
"url": "cccccccccccccc",
"created_at": "2019-09-06T08:40:41Z",
"updated_at": "2019-09-06T13:25:46Z"
},
"entity": {
"name": "app4",
"b_enabled": false,
"d_url": "xxxxxs"
}
},
{
"metadata": {
"id": "vvvvvvvvvvfff",
"url": "cccccccccccccc",
"created_at": "2019-09-06T08:40:41Z",
"updated_at": "2019-09-06T13:25:46Z"
},
"entity": {
"name": "app5",
"b_enabled": false,
"d_url": "xxxxxs"
}
}
]
let output = {};
// we parse each element of the json array
for(let i = 0; i < json.length; i ++ ) {
// we get the current element.
let currentElement = json[i];
// here, we are using the name of the entity as the key and the id of the metadata as the value
output[currentElement.entity.name] = currentElement.metadata.id;
}
console.log(output);（Spring Boot application），该用户使用的是jar jar main-app，并提到它是应用程序client-app.jar的依赖项。
现在，我想使用main-app从@Autowire注入bean。为此，我必须在我的client-app应用程序上添加@ComponentScan。
但是有一种方法可以通过更改main-app上的代码来使main-app上的任何内容都不需要。
答案 0 :(得分：0)
是的，您可以按照sub-package来创建main-app，假设main-app具有包com.example.main-app的以下根，然后在您的client-app上，创建类似com.example.main-app.client-app之类的内容，然后主应用程序将扫描其基本程序包，并且外观也将为client-app。