我忘记了,我想从projecten
表pstatus
中获取一个结果,该表的值仅为2,有人帮助我吗?
$result = mysqli_query($mysqli, "SELECT * FROM projecten ORDER BY pstatus =2 only DESC");
需要成为
$result = mysqli_query($mysqli, "SELECT * FROM projecten WHERE pstatus = 2 ORDER BY pstatus DESC");
好的,固定的,谢谢,你们真是太棒了,在这种情况下,我该如何过滤多个值,仅pstatus 0和1,..
答案 0 :(得分:1)
您可以使用WHERE
选择满足条件的数据。
$result = mysqli_query($mysqli, "SELECT * FROM projecten WHERE pstatus = 2");
答案 1 :(得分:0)
您需要WHERE
声明:
"SELECT * FROM projecten WHERE pstatus = 2"